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Tanya [424]
3 years ago
10

What function does the shape of the star-nosed mole’s nose serve?

Physics
1 answer:
horsena [70]3 years ago
6 0
Hello!

The shape of the star-nosed mole's nose helps it to take away the excess heat.

Letter b)

Hugs!
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A liquid is flowing through a horizontal pipe whose radius is m. The pipe bends straight upward through a height of 10.6 m and j
zaharov [31]

Answer:

Volume flow rate = 1.81 * 10^{-2} meter cube per second

Explanation:

As we know that the

Pressure at the two ends would be the same along with volume of flow.

i.e

P_1 = P_2

and

A_1 V_1 = A_2 V_2

Re arranging the file, we get -

V_1 = \frac{A_2 V_2}{A_1}

The flow equation is

\frac{1}{2}\rho * V_1^2 = \frac{1}{2}\rho * V_2^2 + \rho * g * h\\

Substituting the value of V_1 in above equation, we get -

V_2 = \sqrt{\frac{2gh}{(\frac{A_2}{A_1})^2-1} }

Substituting the given values in above equation we get

V_2 = \sqrt{\frac{2*9.8*10.6}{(\frac{\pi 0.04^2}{\pi 0.02^2} )^2 -1} }\\ V_2 = 3.61 m

Volume flow rate

Q_2 = A_2 V_2\\= \pi r_2^2V_2^2\\= 3.14 * 0.04^2 * 3.61 \\= 1.81 * 10^{-2}

7 0
3 years ago
¿Una persona de 60 corriendo a 4 m/s, tiene más energía cinética que un proyectil de 10 gramos a 300 m/s?
Svet_ta [14]

Explanation:

The question says that "Does a 60 kg person running at 4 m/s have more kinetic energy than a 10 gram projectile at 300 m/s ? "

Speed of a person is 4 m/s

Mass of a person is 60 kg

Kinetic energy of a person is : K=\dfrac{1}{2}mv^2

So,

K=\dfrac{1}{2}\times 60\times 4^2\\\\K=480\ J

Mass of a projectile is 10 grams or 0.01 kg

Speed of a projectile is 300 m/s

Kinetic energy of a projectile is :

K=\dfrac{1}{2}mv^2

K=\dfrac{1}{2}\times 0.01\times (300)^2\\\\K=450\ J

So, it is clear that the kinetic energy of a person is more than that of the kinetic energy of a projectile.

8 0
3 years ago
a ball dropped from a height of 10 meters will bounce more times before coming to rest than a ball dropped from a height of 5 me
Contact [7]

Answer:

plz mark brainliest again lol :)

Explanation:

When you drop a ball from a greater height, it has more kinetic energy just before it hits the floor and stores more energy during the bounce—it dents farther as it comes to a stop.

3 0
3 years ago
A sound wave has a frequency of 300 Hz. If the wavelength is .50 m, then what is the speed of
kherson [118]

Answer:

15000 m/s

Explanation:

You just need to multiply the wavelength with the frequency.

7 0
3 years ago
A Hooke's law spring is mounted horizontally over a frictionless surface. The spring is then compressed a distance d and is used
zloy xaker [14]

Answer:

The compression is \sqrt{2} \  d.

Explanation:

A Hooke's law spring compressed has a potential energy

E_{potential} = \frac{1}{2} k (\Delta x)^2

where k is the spring constant and \Delta x the distance to the equilibrium position.

A mass m moving at speed v has a kinetic energy

E_{kinetic} = \frac{1}{2} m v^2.

So, in the first part of the problem, the spring is compressed a distance d, and then launch the mass at velocity v_1. Knowing that the energy is constant.

\frac{1}{2} m v_1^2 = \frac{1}{2} k d^2

If we want to double the kinetic energy, then, the knew kinetic energy for a obtained by compressing the spring a distance D, implies:

2 * (\frac{1}{2} m v_1^2) = \frac{1}{2} k D^2

But, in the left side we can use the previous equation to obtain:

2 * (\frac{1}{2} k d^2) = \frac{1}{2} k D^2

D^2 =  \frac{2 \ (\frac{1}{2} k d^2)}{\frac{1}{2} k}

D^2 =  2 \  d^2

D =  \sqrt{2 \  d^2}

D =  \sqrt{2} \  d

And this is the compression we are looking for

3 0
4 years ago
Read 2 more answers
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