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3 years ago

Paco pulls a 67 kg crate with 738 N and of force across a frictionless floor 9.0 M how much work does he do in moving the crate

Physics

1 answer:

olga_2 [115]3 years ago

5 0

Answer:

W = 6642 J

Explanation:

Given that,

Mass of a crate, m = 67 kg

Force with which the crate is pulled, F = 738 N

It is moved 9 m across a frictionless floor

We need to find the work done in moving the crate. Let the work done is W. It is given by :

W = F d

W = 738 N × 9 m

= 6642 J

So, the work done is 6642 J.

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A string, stretched between two fixed posts, forms standing-wave resonances at 325 Hz and 390 Hz. What is the largest possible v

Pavel [41]

Answer:

Explanation:

The resonant frequencies for a fixed string is given by the formula nv/(2L).

Where n is the multiple .

v is speed in m/s .

The difference between any two resonant frequencies is given by v/(2L)= fn+1 – fn

fundamental frequency means n=1

i.e fn+1 – fn = 390 -325

= 65

3 0

3 years ago

1. Define weight

andrezito [222]

1. Weight is the gravitational pull with which the earth attracts the body towards the center of the earth. The S.I unit is Newton (N)

2. The weight of an object is related to its mass with the below equation.

W = mg

Where W = weight, m = mass and g = acceleration due to gravity

3. The mass m = 50 kg and g = 9.8 m/ $s^{2}$

Substitute the parameters in the equation above.

W = 50 x 9.8

W = 490 N

4. An object is accelerating when it speeds up. If the object slows down, it means it is decelerating. The correct answer is option A

5. Newton's second law of motion is:

F = ma

Where F = force applied, m = mass and a = acceleration

Therefore, Newton's second law of motion relates an object's acceleration to its net force acting on it. The correct answer is option C

6. According to Newton's second law of motion which relates an object's acceleration to its mass, doubling the net force acting on an object a doubles its acceleration. Because mass is always constant.

7. Since the weight of an object is related to its mass with the equation.

W = mg, If the mass of an object doubles, its weight will also doubles. Option A is the correct answer.

8. If you know the mass of an object, you can calculate its weight with the formula F = mX when X = 9.8m/ $s^{2}$

9. Force is expressed in unit as Newton (N)

10. The parameters given are :

mass m = 20kg

Force F = 40N

To calculate acceleration, use the formula F = ma

Substitute all the parameters into the equation.

40 = 20a

a = 40/20

a = 2m/ $s^{2}$

The correct option is D

Learn more here : brainly.com/question/18835375

8 0

3 years ago

What is a type of pulley that increases the size and effort of force

12345 [234]

The answer is Movable

5 0

3 years ago

A person hears sound wave beast at 3000Hz at the temperature of 30 °C. What is the person's ear canal length? Please explain

Evgen [1.6K]

Answer:

The person's ear canal length is 2.91 cm.

Explanation:

Given that,

Frequency = 3000 Hz

Temperature = 30°C

We need to calculate the speed

Using equation of sound wave with temperature

[texs]v(t)=331+0.6\times T[/tex]

Put the value of T

$v(t)=331+0.6\times30^{\circ}\ C$

$v(t)=349\ m/s$

We need to calculate the length

Using formula of closed organ pipe

$f=\dfrac{v}{4L}$

$L=\dfrac{v}{4f}$

Where, L = length

v = velocity

f = frequency

Put the value into the formula

$L=\dfrac{349}{4\times3000}$

$L=0.0291\ m$

$L=2.91\times10^{-2}\ m$

$L=2.91\ cm$

Hence, The person's ear canal length is 2.91 cm.

4 0

3 years ago

Select the correct answer.

Ilia_Sergeevich [38]

Pretty sure it is B.
Because inertia is a tendency to do nothing or remain unchanged.

8 0

2 years ago