Answer:
Entropy of the universe is constantly increasing.
Explanation:
Entropy is the loss of available energy when it is in transit. The entropy of a system increases consuming the energy, this energy is now unavailable for doing the work or making the corresponding changes in the property of a system.
Entropy is the measure of randomness of a system. It is a toll that the nature takes for energy in transit.
The second law of thermodynamics concludes that all the energy cannot be transformed from one form to another and the flow of energy has a specific direction.
If a reversible process occurs, there is no net change in entropy. In an irreversible process, entropy always increases, so the change in entropy is positive. The total entropy of the universe is continuously increasing.
Answer:
The formula for Impedance for circuit with R, C, and L are:

The impedance Z of the series RLC circuit depend upon angular frequency ω. Impedance is measured in ohms and resistance (R), inductance reactance and capacitive reactance. Series RLC circuit consist of the resistance, a capacitance and an inductance connected in the circuits. Electrical impedance is the measurement of the opposition that a circuit present in a current.
Answer:
Bulb 1 has more resistance.
Explanation:
Given that,
Two lightbulbs work on a 120-V circuit.
The power of circuit 1, P₁ = 50 W
The power of circuit 2, P₂ = 100 W
We need to find the bulb that has a higher resistance.
The power of the bulb is given by :

For bulb 1,

For bulb 2,

So, bulb 1 has higher resistance.
Ke = (1/2)mv²
m = 100kg, v = 10 km/s = 10*1000 = 10000m/s
Ke = (1/2)*100*10000
Ke = 500000 Joules