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2 answers:
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Answer:
a)
b) Ball 1 has a greater speed than ball 2 when they are passing.
c) The height is the same for both balls = 3h/4.
Explanation:
a) We can find the time when the two balls meet by equating the distances as follows:
Where:
: is the initial height = h
: is the initial speed of ball 1 = 0 (it is dropped from rest)
(1)
Now, for ball 2 we have:
Where:
: is the initial height of ball 2 = 0
(2)
By equating equation (1) and (2) we have:
Where the initial velocity of the ball 2 is:
Since = 0 at the maximum height (h):
Hence, the time when they pass each other is:
b) When they are passing the speed of each one is:
For ball 1:
The minus sign is because ball 1 is going down.
For ball 2:
Therefore, taking the magnitude of ball 1 we can see that it has a greater speed than ball 2 when they are passing.
c) The height of the ball is:
For ball 1:
For ball 2:
Then, when they are passing the height is the same for both = 3h/4.
I hope it helps you!
Answer:
Explanation:
The energy lost due to air friction is equal to the mechanical energy lost by the parachutist during the fall.
The initial mechanical energy of the parachutist (at the top) is equal to his gravitational potential energy:
where
m = 20.1 kg is his mass
is the acceleration due to gravity
h = 662 m is the initial heigth
The final mechanical energy (at the bottom) is equal to his kinetic energy:
where
v = 7.12 m/s is the final speed of the parachutist
Therefore, the energy lost due to air friction is: