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snow_tiger [21]
3 years ago
11

if the velocity of a car is halved the fc required to keeo it in a path of constant radius is multiplied/divided by?

Physics
2 answers:
damaskus [11]3 years ago
7 0
I believe this is it
The centripetal force is given by
F = mv^2 / r
When v' = v/2,
F' = mv'^2/r = m(v/2)^2/r = mv^2/4r = F/4.
So the centripetal force is divided by 4.
Crank3 years ago
3 0
It should be the 4... so the answer is 4...
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4 years ago
A 40-kg rock is dropped from an elevation of 10 m. What is the velocity of the rock when it is 5-m from the ground?
ivolga24 [154]

Answer:

Explanation:

Given

mass of rock m=40\ kg

Elevation of Rock h=10\ m

Distance traveled by rock with time

h=ut+\frac{1}{2}at^2

where, u=initial velocity

t=time

a=acceleration

here initial velocity is zero

when rock is 5 m from ground then it has traveled a distance of 5 m from top because total height is 10 m

5=0\times t+\frac{1}{2}(9.8)(t^2)

t^2=\frac{10}{9.8}

t=1.004\approx 1\ s

velocity at this time

v=u+at

v=0+9.8\times 1.004

v=9.83\ m/s

6 0
4 years ago
Why is Energy not created nor destroyed?<br> (Need the answer ASAP!!)
eduard

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4 0
3 years ago
An aquifer pump test was conducted in a confined aquifer where the initial piezometric surface was at elevation 12.45 m, and wel
murzikaleks [220]

Answer:

T = 0.0088 m²/s

Explanation:

given,

initial piezometric elevation = 12.5 m

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we know                              

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k = 0.629 mm/sec

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T = k × H                          

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3 years ago
Which current is produced in homes
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6 0
3 years ago
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