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Eduardwww [97]
4 years ago
10

What is the metric unit for time?

Physics
1 answer:
spin [16.1K]4 years ago
5 0
The base unit of time in the metric and SI system is the second.
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You have a resistor of resistance 200 ? and a 6.00-?F capacitor. Suppose you take the resistor and capacitor and make a series c
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Explanation:

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4 years ago
. You have completed your design of a new surgical headlamp. You have decided to power the headlamp using four AA rechargeable b
SSSSS [86.1K]

Answer:

LED run before the batteries are depleted is 3.87 hours

Explanation:

given data

battery = 4 AA

battery is rated = 1.2V, 2550 mAh

power = 3 W

efficient = 95%

to find out

How long will the LED run before the batteries are depleted

solution

we consider here power delivered by battery is = x

so power = x × efficient

3 = x 95%

x = 3.15 W

and

voltage by 4 battery is = 4 × 1.2 = 4.8 V

so current will be = \frac{x}{volatge}

current = \frac{3.15}{4.8}

current = 0.6577 A

so total discharge hours = \frac{2550}{current}

total discharge hours = \frac{2550}{657.7}

time = 3.87 hours

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5 0
3 years ago
Solenoid 2 has twice the diameter, twice the length, and twice as many turns as solenoid 1. How does the field B2 at the center
klemol [59]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The correct option is  option 3

Explanation:

From the question we are told that

   The diameter of solenoid 1 is  d_1

   The length of solenoid 1 is   L_1

    The  number of turns of solenoid is  N_1

   The diameter of solenoid 2 is  d_2 = 2d_1

   The length of solenoid 2 is   L_2 = 2L_1

    The  number of turns of solenoid  2 is    N_2 = 2 N_1

Generally the magnetic in a solenoid is mathematically represented as

     B  =  \frac{\mu_o *  N  *  I }{L}

From this equation we see that

     B  \ \alpha \  \frac{N}{L}

     B   =  C   \frac{N}{L}

Here C stands for constant

=>   C =  \frac{B *  \frac{L}{N}

=>    \frac{B_1 *  \frac{L_1}{N_1}   = \frac{B_2 *  \frac{L_2}{N_2}

=>  \frac{B_1}{B_2 }  =  \frac{N_1 L _2}{ N_2L_1}

=>   \frac{B_1}{B_2 }  =  \frac{N_1 * (2 L_1)}{ (2 N_2)L_1}

=>   \frac{B_1}{B_2 }  =  1

=>   B_2 = B_1

4 0
4 years ago
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