Force = (mass) x (acceleration)
If the full 15N is pointing parallel to the ground,
then
15 N = (58 kg) x (acceleration).
Divide each side
by 58 kg: Acceleration = 15 N / 58 kg
= (15 kg-m/s²) / (58 kg)
= (15/58) (kg-m/kg-s²)
= 0.26 m/s² .
Answer:

Explanation:
In a LC circuit The time constant τ is the time necessary for 60% of the total current (maximum current), pass through the inductor after a direct voltage source has been connected to it. The time constant can be calculated as follows:

Therefore, the time needed for the current to reach a fraction f = 0.6(60%) of its maximum value is:

The total energy (also called mechanical energy) is the sum of the kinetic energy and potential energy:

For this pendulum, we see that at t=0.60 s the total energy is TE=0.918 J while the potential energy is 0.054 J, so the kinetic energy (the missing value in the table) is
Answer:
<h2>Non-Ionizing Radiation From Wireless Technology
</h2>
Radiofrequency (RF) energy is a type of electromagnetic radiation. It is used to transmit signals carrying information in the form of radio waves. Radio waves are broadcast using a transmitter. When the radio waves reach a receiver, the signal is converted back into the information that was originally sent by the transmitter. When you talk on a cell phone, your cell phone acts as a transmitter and your voice is carried on radio waves to the person you are calling. Their phone acts as the receiver and converts the signal back into your voice. In addition to cell phones, other wireless devices such as radios, Wi-Fi routers, satellites, radars and pacemakers can send or receive RF energy waves.
Answer:
The current on the water layer = 1.64×10^-3A
Explanation:
Let's assume that the radius given for the string originates from the centre of the string. The equation for determining the current in the water layer is given by:
I = V × pi[(Rwater + Rstring)^2 - (Rstring)^2/ ( Resitivity × L)
I =[ 166×10^6 ×3.142[(0.519×10^-4) + (2.15×10^-3])^2 - ( 2.15×10^-3)^2] / ( 183 × 831)
I =[ 521572000(4.848×10^6)- 4.623×10^-6]/ 154566
I = 252.83 -(4.623×10^-6)/ 154566
I = 252.83/154566
I = 1.64× 10^-3A