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Mrrafil [7]
3 years ago
11

The maximum oxygen uptake is known as the

Physics
1 answer:
grandymaker [24]3 years ago
3 0
<span>The maximum oxygen uptake is known as the VO max.</span>
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If fluorine was in ionic compounds with ions of each of the following atoms, how many fluorines would be needed?
nevsk [136]
<span>You forgot to post the list of "following atoms", but 

Fluorine ions have a -1 charge. So find the charges of the other ions and The number of Fluorines you'll need should match the </span>other ion's charge.
8 0
3 years ago
Three children are riding on the edge of a merry-go-round that is a solid disk with a mass of 102 kg and a radius of 1.53 m. The
Mnenie [13.5K]

Three children of masses and their position on the merry go round

M1 = 22kg

M2 = 28kg

M3 = 33kg

They are all initially riding at the edge of the merry go round

Then, R1 = R2 = R3 = R = 1.7m

Mass of Merry go round is

M =105kg

Radius of Merry go round.

R = 1.7m

Angular velocity of Merry go round

ωi = 22 rpm

If M2 = 28 is moves to center of the merry go round then R2 = 0, what is the new angular velocity ωf

Using conservation of angular momentum

Initial angular momentum when all the children are at the edge of the merry go round is equal to the final angular momentum when the second child moves to the center of the merry go round  Then,

L(initial) = L(final)

Ii•ωi = If•ωf

So we need to find the initial and final moment of inertia

NOTE: merry go round is treated as a solid disk then I= ½MR²

I(initial)=½MR²+M1•R²+M2•R²+M3•R²

I(initial) = ½MR² + R²(M1 + M2 + M3)

I(initial) = ½ × 105 × 1.7² + 1.7²(22 + 28 + 33)

I(initial) = 151.725 + 1.7²(83)

I(initial) = 391.595 kgm²

Final moment of inertial when R2 =0

I(final)=½MR²+M1•R²+M2•R2²+M3•R²

Since R2 = 0

I(final) = ½MR²+ M1•R² + M3•R²

I(final) = ½MR² + (M1 + M3)• R²

I(final)=½ × 105 × 1.7² + ( 22 +33)•1.7²

I(final) = 151.725 + 158.95

I(final) = 310.675 kgm²

Now, applying the conservation of angular momentum

L(initial) = L(final)

Ii•ωi = If•ωf

391.595 × 22 = 310.675 × ωf

Then,

ωf = 391.595 × 22 / 310.675

ωf = 27.73 rpm

Answer: So, the final angular momentum is 27.73 revolution per minute

7 0
3 years ago
Transverse waves are sent along a 4.50 m long string with a speed of 85.00 m/s. The string is under a tension of 20.00 N. What i
frutty [35]

Answer:

m = 0.0125 kg

Explanation:

Let us apply the formula for the speed of a wave on a string that is under tension:

v = \sqrt{\frac{F}{\mu} }

where F = tension force

μ = mass per unit length

Mass per unit length is given as:

μ  = m / l

where m = mass of the string

l = length of the string

This implies that:

v = \sqrt{\frac{F}{m/l} }\\ \\v = \sqrt{\frac{F * l}{m} }

Let us make mass, m, the subject of the formula:

v^2 = \frac{F * l}{m}\\\\m = \frac{F * l}{v^2}

From the question:

F = 20 N

l = 4.50 m

v = 85 m/s

Therefore:

m = \frac{20 * 4.5}{85^2}\\\\m = \frac{90}{7225}\\ \\m = 0.0125 kg

5 0
2 years ago
Strong evidence for the existence of dark matter comes from observations of
adoni [48]

Answer:

NASA's Chandra X-ray Observatory and other telescopes such as the Hubble telescope.

Explanation:

Dark matter and normal matter have been wrenched apart by the tremendous collision of two large clusters of galaxies.

The above observations have provided the strongest evidence yet that most of the matter in the universe is dark.

5 0
2 years ago
What is the power of a diverging lens of focal length 0.4 m
romanna [79]

Answer:

-2.5 is the answer to your question

4 0
2 years ago
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