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2 years ago

Please HELP!!!!! Will give brainlyest!!! (Image attached.)

Mathematics

1 answer:

Andreas93 [3]2 years ago

8 0

Answer:

18 because you use the middle section which explains how many rolls are needed

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Find the area of the trapezoid. Pls explain and I will mark brainliest.

timama [110]

Answer:

B. 191.4 m²

Step-by-step explanation:

Split the trapezoid as pictured below

Find its height and the upper base, then find the area of the trapezoid.

There are 3 pieces, two of them are 45°×45° and 30°×60°×90° triangles

The ratio of sides of a 30°×60°×90° triangle is 1 : √3 : 2
The legs of a 45x45 triangle are equal

The above mentioned properties give us:

h = 16/2 = 8 m
b = 8√3 ≈ 13.85 m
a = h = 8 m

Now find the area:

A = 1/2( 13 + 8 + 13.85 + 13)*8 = 191.4 m²

Correct choice is B

8 0

2 years ago

Drag and drop ? HELP ME PLEASE!!!

Eva8 [605]

Answer:the first one goes in the both category, the second one goes in the neither category, the third one goes in the x-intercept category and the last one goes in the y-intercept category

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

What is the scientfic notation of 0.05

vredina [299]

Answer:

5×10⁻²

Step-by-step explanation:

Move the decimal so there is one non-zero digit to the left of the decimal point.
The number of decimal places you move will be the exponent on the 10. a. If the decimal is being moved to the right, the exponent will be negative.

b. If the decimal is being moved to the left, the exponent will be positive.

Therefore. The answer is 5×10⁻²

8 0

2 years ago

Plz help fast. What is the value of x?

beks73 [17]

Answer is 7.b because of the angles

3 0

2 years ago

The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e

I am Lyosha [343]

Answer:

(a) The proportion of tenth graders reading at or below the eighth grade level is 0.1673.

(b) The 95% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.198, 0.260).

Step-by-step explanation:

Let X = number of students who read above the eighth grade level.

(a)

A sample of n = 269 students are selected. Of these 269 students, X = 224 students who can read above the eighth grade level.

Compute the proportion of students who can read above the eighth grade level as follows:

$\hat p=\frac{X}{n}=\frac{224}{269}=0.8327$

The proportion of students who can read above the eighth grade level is 0.8327.

Compute the proportion of tenth graders reading at or below the eighth grade level as follows:

$1-\hat p=1-0.8327$

$=0.1673$

Thus, the proportion of tenth graders reading at or below the eighth grade level is 0.1673.

(b)

the information provided is:

n = 709

X = 546

Compute the sample proportion of tenth graders reading at or below the eighth grade level as follows:

$\hat q=1-\hat p$

$=1-\frac{X}{n}$

$=1-\frac{546}{709}$

$=0.2299\\\approx 0.229$

The critical value of z for 95% confidence interval is:

$z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

Compute the 95% confidence interval for the population proportion as follows:

$CI=\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

$=0.229\pm 1.96\times \sqrt{\frac{0.229(1-0.229)}{709}}\\=0.229\pm 0.03136\\=(0.19764, 0.26036)\\\approx (0.198, 0.260)$

Thus, the 95% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.198, 0.260).

5 0

3 years ago