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4 years ago

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Mathematics

1 answer:

miss Akunina [59]4 years ago

3 0

We are going to use cosine because it is adjacent over hypotenuse and we are trying to find the length of the adjacent side.
$cos (theta) = \frac{adj}{hyp} \\ theta = 41 \\ hyp = 11 \\ cos(41) = \frac{x}{11} \\ 11*cos(41) = 11* \frac{x}{11} \\ 11 * 0.7547 = x \\ x = 8.302$

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Marissa has a photograph that measures 2 in. by 4 in. She has mounted the picture on a mat so that there is a border that measur

DanielleElmas [232]

Step-by-step explanation:

The initial image of the photo is 2 in by 4 in. The mat is 4 in by 6 in.

The new image is dilated by a scale of 2. So we double the dimensions. The new photo is 4 in by 8 in. The new mat is 8 in by 12 in.

3 0

3 years ago

Classify is the function as increasing decreasing or constant l

timama [110]

Answer:

Increasing

Step-by-step explanation:

Remember that f(x) is the same as y in slope intercept form y = mx + b.

We don’t have a number for “b” which means the line goes across the origin.

Since 5 replaces m, that is the slope and since it’s positive, it is increasing.

Best of Luck!

5 0

3 years ago

PLEASE HELP!!!!

emmasim [6.3K]

Answer:

Step-by-step explanation:

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4 0

3 years ago

Read 2 more answers

Mario invests £2000 for 3 years at 5% per annum compound interest. Calculate the value of the investment at the end of 3 years.

Delicious77 [7]

Answer:

$2315.25

Step-by-step explanation:

Given data

Principal= £2000

Time= 3 years

Rate= 5%

The compound interest expression is

A= P(1+r)^t

substitute

A= 2000(1+0.05)^3

A= 2000(1.05)^3

A= 2000*1.157625

A= 2315.25

Hence the Amount is $2315.25

7 0

3 years ago

Suppose Upper F Superscript prime Baseline left-parenthesis x right-parenthesis equals 3 x Superscript 2 Baseline plus 7 and Upp

Sedaia [141]

It looks like you're given

F'(x) = 3x² + 7

and

F (0) = 5

and you're asked to find F(b) for the values of b in the list {0, 0.1, 0.2, 0.5, 2.0}.

The first is done for you, F (0) = 5.

For the remaining b, you can solve for F(x) exactly by using the fundamental theorem of calculus:

$F(x)=F(0)+\displaystyle\int_0^x F'(t)\,\mathrm dt$

$F(x)=5+\displaystyle\int_0^x(3t^2+7)\,\mathrm dt$

$F(x)=5+(t^3+7t)\bigg|_0^x$

$F(x)=5+x^3+7x$

Then F (0.1) = 5.701, F (0.2) = 6.408, F (0.5) = 8.625, and F (2.0) = 27.

On the other hand, if you're expected to approximate F at the given b, you can use the linear approximation to F(x) around x = 0, which is

F(x) ≈ L(x) = F (0) + F' (0) (x - 0) = 5 + 7x

Then F (0) = 5, F (0.1) ≈ 5.7, F (0.2) ≈ 6.4, F (0.5) ≈ 8.5, and F (2.0) ≈ 19. Notice how the error gets larger the further away b gets from 0.

A better numerical method would be Euler's method. Given F'(x), we iteratively use the linear approximation at successive points to get closer approximations to the actual values of F(x).

Let y(x) = F(x). Starting with x₀ = 0 and y₀ = F(x₀) = 5, we have

x₁ = x₀ + 0.1 = 0.1

y₁ = y₀ + F'(x₀) (x₁ - x₀) = 5 + 7 (0.1 - 0) → F (0.1) ≈ 5.7

x₂ = x₁ + 0.1 = 0.2

y₂ = y₁ + F'(x₁) (x₂ - x₁) = 5.7 + 7.03 (0.2 - 0.1) → F (0.2) ≈ 6.403

x₃ = x₂ + 0.3 = 0.5

y₃ = y₂ + F'(x₂) (x₃ - x₂) = 6.403 + 7.12 (0.5 - 0.2) → F (0.5) ≈ 8.539

x₄ = x₃ + 1.5 = 2.0

y₄ = y₃ + F'(x₃) (x₄ - x₃) = 8.539 + 7.75 (2.0 - 0.5) → F (2.0) ≈ 20.164

4 0

3 years ago