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3 years ago

Can two charged

Physics

1 answer:

miss Akunina [59]3 years ago

3 0

Answer:

yes they can,

Electrostatic forces are non-contact forces; they pull or push on objects without touching them. Rubbing some materials together can result in something called 'charge' being moved from one surface to the other.

Explanation:

example: the opposite ends of magnets

hope this helps! have a wonderfull day!

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Explain three differences between a science and a pseudoscience.

grin007 [14]

1) science does not accept personal story's as evidence, pseudoscience relies on these story's as evidence.
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4 years ago

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frutty [35]

The correct answer is the wavelength of the light. Good luck m8

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Given a double slit apparatus with slit distance 2 mm, what is the theoretical maximum number of bright spots that I would see w

katen-ka-za [31]

Answer:

The values is $m_{max} = 8001 \ bright \ spots$

Explanation:

From the question we are told that

The slit distance is $d = 2 \ mm = 2*10^{-3} \ m$

The wavelength is $\lambda = 500 \ nm = 500 *10^{-9} \ m$

At the first half of the screen from the central maxima

The number of bright spot according to the condition for constructive interference is

$n = \frac{d * sin (\theta )}{\lambda}$

For maximum number of spot $\theta = 90^o$

$n = \frac{2*10^{-3} * sin (90 )}{500 *10^{-9}}$

$n =4000$

Now for the both sides plus the central maxima we have

$m_{max} = 2 * n + 1$

substituting values

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4 years ago

in three situations, a briefly applied horizontal force changes the velocity of a hockey puck that slides over frictionless ice.

victus00 [196]

The work done on the Puck by the applied force from the most positive to the most negative is c, b, a respectively.

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F = ma

$F= \frac{mv}{t}$

The force applied to an object increases with increases in the velocity of the object.

In the given diagram, the resultant velocity of the puck is calculated as follows;

Figure a:

$\Delta v = v_f -v_i\\\\\Delta v = 5 - 6 = - 1 \ m/s$

Figure b:

$v = \sqrt{4^2 + 3^2} \\\\v = 5 \ m/s$

Figure c:

$\Delta v = 4 - (-2)\\\\\Delta v = 6 \ m/s$

Thus, the work done on the Puck by the applied force from the most positive to the most negative is c, b, a respectively.

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