Sin of a right triangle is opposite divided by hypotenuse
in this case, that is 5/8.6 = 0.581395349<span>
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you can easily remember the trig functions with this acronym:
SOH-CAH-TOA
S: Sine
O: Opposite
H: Hypotenuse
C: Cosine
A: Adjacent
H: Hypotenuse
T: Tangent
O: Opposite
A: Adjacent
Answer:
0.239 T
Explanation:
Applying,
F = Bvqsin∅................ Equation 1
Where F = magnetic force, B = magnetic Field, q = charge of a proton, v = velocity of proton, ∅ = angle between the velocity and the magnetic field.
make B the subject of the equation
B = F/(vqsin∅)................. Equation 2
From the question,
Given: F = 1.15×10⁻¹³ N, v = 3.0×10⁶ m/s, ∅ = 90°(perpendicular)
Constant: q = 1.602 x 10⁻¹⁹ C
Substitute into equation 2
B = 1.15×10⁻¹³ /(3.0×10⁶×1.602 x 10⁻¹⁹×sin90°)
B = 1.15×10⁻¹³/(4.806×10⁻¹³)
B = 0.239 T.
Hence the magnetic field = 0.239 T
Answer;
A)S(t)=96t-16t² +432
B)it will take 9 seconds for the ball to reach the ground.
C)864feet
Explanation:
We were given an initial height of 432 feet.
And v(t)= 96-32t
A) we are to Find s(t), the function giving the height of the ball at time t
The position, or heigth, is the integrative of the velocity. So
S(t)= ∫(96-32)dt
S(t)=96t-16t² +K
S(t)=96t-16t² +432
In which the constant of integration K is the initial height, so K= 432
b) we need to know how long will the ball take to reach the ground
This is t when S(t)= 0
S(t)=96t-16t² +432
-16t² +96t +432=0
This is quadratic equation, if you solve using factorization method we have
t= -3 or t= 9
Therefore, , t is the instant of time and it must be a positive value.
So it will take 9 seconds for the ball to reach the ground.
C)V=s/t
Velocity= distance/ time
=96=s/9sec
S=96×9
=864feet
Answer:
Light provides brightness to see and also light carries energy
The force of friction is that force that tends to oppose the motion of the body with the surface in contact... are you clear with it?
