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pishuonlain [190]
2 years ago
13

Nuclear Equations HELP!!! 100PTS

Chemistry
2 answers:
hjlf2 years ago
7 0
Hopes this helps:

Answer:

A balanced nuclear equation is one where the sum of the mass numbers (the top number in notation) and the sum of the atomic numbers balance on either side of an equation.

SpyIntel [72]2 years ago
3 0

A nuclear equation is one, where the sum of the mass numbers and the sum of the atomic numbers balance on either side of an equation. Nuclear equation problems will often be given such that one particle is missing.

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How are the properties of organic compounds determined?
Harman [31]

Explanation:

The physical properties of organic compounds typically of interest include both quantitative and qualitative features. Quantitative information includes a melting point, boiling point, and index of refraction. Qualitative properties include odor, consistency, solubility, and color.

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Solutions of aluminum nitrate and sodium sulfate react to form sodium nitrate and aluminum sulfate. Classify this reaction.
Temka [501]
C is the correct answer. Double displacement reaction, also called as metathesis, is a type of reaction wherein two compounds react to form new compounds. This case the cations and the anions of the reactants replace each other forming the new compounds.
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What ALWAYS occurs simultaneously with reduction?
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Read 2 more answers
A chemist makes up a solution by dissolving 42.0 g of Mg(NO3)2 in enough water to produce a final solution volume of 259 mL. To
Igoryamba

Answer:

The molar mass of Mg(NO₃)₂, 148.3 g/mol.

Explanation:

Step 1: Given data

  • Mass of Mg(NO₃)₂ (solute): 42.0 g
  • Volume of solution: 259 mL = 0.259 L

Step 2: Calculate the moles of solute

To calculate the moles of solute, we need to know the molar mass of Mg(NO₃)₂, 148.3 g/mol.

42.0 g × 1 mol/148.3 g = 0.283 mol

Step 3: Calculate the molarity of the solution

M = moles of solute / liters of solution

M = 0.283 mol / 0.259 L

M = 1.09 M

7 0
2 years ago
How many atoms are present in a 0.600- mole sample of gold?
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