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pishuonlain [190]
2 years ago
13

Nuclear Equations HELP!!! 100PTS

Chemistry
2 answers:
hjlf2 years ago
7 0
Hopes this helps:

Answer:

A balanced nuclear equation is one where the sum of the mass numbers (the top number in notation) and the sum of the atomic numbers balance on either side of an equation.

SpyIntel [72]2 years ago
3 0

A nuclear equation is one, where the sum of the mass numbers and the sum of the atomic numbers balance on either side of an equation. Nuclear equation problems will often be given such that one particle is missing.

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Consider the Fischer ester synthesis of methyl benzoate from benzoic acid and methanol in the presence of sulfuric acid as a cat
zlopas [31]

Answer:

48.8%

Explanation:

The reaction has a 1:1 mole ratio so;

Number of moles of benzoic acid reacted = mass/molar mass = 3.8 g/122.12 g/mol = 0.03 moles

So;

0.03 moles of methyl benzoate is formed in the reaction

Mass of methyl benzoate formed = 0.03 moles * 136.15 g/mol = 4.1 g

percent yield = actual yield/theoretical yield * 100/1

percent yield = 2.0 g/4.1 g * 100 = 48.8%

4 0
3 years ago
H2S (g) + O2(g) -> SO2+ H2O, how many grams of O2 are needed to make 25.0 g of SO2 (Hint: balance the equation first)
vekshin1

Answer:

Hello

The answer is 18,7(b)

Explanation:we don't know the value of o² so at first we should put (x)instead of gr of o²and then write 1molO²/32grO²×2mol SO²/3mol O²×64gr SO²/1molSO²=25 gr SO².and then just find the value of (x).

5 0
3 years ago
If Marie and Calvin dissolve 50 grams of KBr in 100 grams of water at 90oC, the solution is
hram777 [196]

Answer:

The solution is 50 %wt

Explanation:

50% wt is a sort of concentration and means, that 50 g of solute (in this case, the potassium bromide) dissolved in 100 g of water.

It is the same to say, that there are 50g of KBr for every 100g of H₂O

8 0
3 years ago
Which statements are true of a heterozygous mixture ?
Maksim231197 [3]

Answer:

b

Explanation:

2 +4

3 0
3 years ago
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Based on the synthesis reaction, what would the product of the reaction be? NaPO3 + CuO → ? NaO + CuPO3 Na + P + Cu + O4 NaCuPO4
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C

Explanation:

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3 years ago
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