<h3>Answer:</h3>
A Phospholipid is formed.
<h3>Explanation:</h3>
The reaction of fatty acids, glycerol and phosphoric acid is given below. In this reaction the carboxylic groups of fatty acids and the hydrogyl groups of glycerol undergo an Esterification Reaction with the elimination of two water molecules and formation of Ester functional group. Also, the third hydroxyl group of glycerol undergo dehydration reaction with phosphoric acid. The resulting molecule is known as phospholipid.
Biologically, Phospholipids are found in the cell membranes. The long hydrocarbon chains of fatty acids acts as hydrophobic (water fearing) tails and the phosphate group acts as hydrophilic (water loving) head. They form a barrier protecting the internal environment of cell from external surrounding.
According to Einstein the energy of photon is given by the equation,
E = hν = h . c/λ
where h is Planck's constant, c is the speed of light, ν is the frequency of light and λ is the wavelength of light.
Given, wavelength = 608 nm = 608 x 10⁻⁹ m
Conversion factor: 1 nm = 10⁻⁹ m
c = 3 x 10⁸ m/s
h = 6.626× 10⁻³⁴ J.s
Substituting the data into the equation we get,
E = h . c/λ
E = 6.626× 10⁻³⁴ J.s x (3 x 10⁸ m/s) / 608 x 10⁻⁹ m
E = 3.27 x 10⁻¹⁹J
3.27 x 10⁻¹⁹J energy must be added to strontium to get it to produce 608 nm wavelength.
Answer: A 13.88 mL of the concentrated acid would be required to make 250. mL of a 1.00 M 
solution.
Explanation:
Given: 
= 18.0 M, 
= ?
= 1.00 M, 
= 250 mL
Formula used to calculate the volume of concentrated acid is as follows.
Substitute the values into above formula as follows.
Thus, we can conclude that 13.88 mL of the concentrated acid would be required to make 250. mL of a 1.00 M solution.
Answer:
NaNO3
Explanation:
Hello,
In this case, the required reaction is an acid-base neutralization reaction which is said to be:
There, we see that the sodium displaced the hydrogen in the nitric acid to form sodium nitrate a very used salt in the industry, so, as a result of that displacement, water is formed as the secondary neutralization product. For the above mentioned, answer is NaNO3
.
Best regards.
Answer:
When your cooking, or baking a cake. For example, If you bake a cake you are adding ingredients to the cake. When you still the cake into the oven all the ingredients are reacting to each other, causing a chemical reaction.
Explanation:
