The oxidation numbers for Nitrogen are respectively -3, +5, +4
Answer:
a)CH₄, BH₃, and CCl₄
Explanation:
<u>London dispersion forces:-
</u>
The bond for example, in the molecule is F-F, which is non-polar in nature because the two fluorine atoms have same electronegativity values.
The intermolecular force acting in the molecule are induced dipole-dipole forces or London Dispersion forces / van der Waals forces which are the weakest intermolecular force.
Out of the given options, H₂O , NH₃ exhibits hydrogen bonding which is:-
<u>Hydrogen bonding:-
</u>
Hydrogen bonding is a special type of the dipole-dipole interaction and it occurs between hydrogen atom that is bonded to highly electronegative atom which is either fluorine, oxygen or nitrogen atom.
Thus option B and C rules out.
<u>Hence, the correct option which represents the molecules which would exhibit only London forces is:- a)CH₄, BH₃, and CCl₄</u>
Answer:
physical
Explanation:
no chemical reaction occurs
Answer:
<h2>6.91 </h2>
Explanation:
To find the pH we must first find the pOH
The pOH can be found by using the formula
pOH = - log [ {OH}^{-} ]
We have
pOH = 7.09
Next we use the equation
pH = 14 - pOH
We have
pH = 14 - 7.09
We have the final answer as
<h3>6.91</h3>
Hope this helps you
Answer:
A number is right I think
