The rate constant for a particular zero-order reaction is 0.075 M s-1. If the initial concentration of reactant is 0.537 M it ta
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Answer:
<h2>91.2</h2>Explanation:
Given that:
Temperature = 60 °C
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
T₁ = (60 + 273.15) K = 333.15 K
n = 5.14 × 10⁻³ mol
V = 1,171 mL = 1.171 L ( 1 mL = 0.001 L)
Using ideal gas equation as:
where,
P is the pressure
V is the volume
n is the number of moles
T is the temperature
R is Gas constant having value = 62.364 L Torr/ K mol
Applying the equation as:
P × 1.171 L = 5.14 × 10⁻³ mol × 62.364 L Torr/ K mol × 333.15 K
<u>⇒P = 91.2 torr</u>