The question is, "how many ways ...".
There are as many ways to solve a math problem as you can think of. (Some are shorter or easier than others.)
Essentially, an infinite number.
Answer:
x^2 + 4y^2 + 6x + 4
Step-by-step explanation:
Arranging the terms;
x ^ 2 + y^2 + 3y^2 + 4x + 2x + 2 + 2
x^2 + 4y^2 + 4x + 2x + 2 + 2
x^2 + 4y^2 + 6x + 2 + 2
x^2 + 4y^2 + 6x + 4
Answer: (2,1)
Step-by-step explanation:
The two equations given are:
y = 3 -x
y = x - 1
The question is asking to determine the point of intersection for two linear functions aka two lines.
Step #1: Both functions must be in slope intercept form which is y = mx+b. In this case, this step can be skipped because both functions are in slope form. At an intersection, x and y must have the same value for each equation. This means that the equations are equal to each other. Therefore, we can set both equations equal to each other to solve for x.
- Add x to both sides to get 2x - 1 = 3
- Add 1 to both sides to get 2x = 4
- Divide both sides by 2 to get x = 2
Step #2: We found the x-coordinate, but we need to find the y-coordinate. We know that the x-coordinate is 2, so substitute the number 2 into any of the given equations. So, either into y = 3 - x or y = x - 1.
The point of intersection is (2,1).
Hope this helps ^_^
The trig function "sin" represents the opposite side / the hypotenuse. Therefore, sinC = c/a
Answer: 9
<u>Step-by-step explanation:</u>
Andre has 4 x (the number of cars Peter has). Andre has 36 cars.
4P = 36
P = 9