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pickupchik [31]
2 years ago
6

Un paquete de 4.5 kg sube desde el suelo hasta una estantería de 2.8 m de altura. Encuentra el aumento de energía potencial

Chemistry
1 answer:
grin007 [14]2 years ago
7 0
Creo que es 12.32 pero no estoy súper segura
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Your apple juice has a molarity of 3.4 M and a volume of 0.895 litres. What does a student have to do to decrease the molarity t
Jlenok [28]

Answer:

4.285 L of water must be added.

Explanation:

Hello there!

In this case, for this dilution-like problems, we need to figure out the final volume of the resulting solution so that we would be able to obtain the correct volume of diluent (water) to be added. In such a way, we can obtain the final volume, V2, as shown below:

M_1V_1=M_2V_2\\\\V_2=\frac{M_1V_1}{M_2}

Thus, by plugging in the initial molarity, initial volume and final molarity (0.587 M) we obtain:

V_2=\frac{3.4M*0.895 L}{0.587M}\\\\V_2=5.18L

It means we need to add:

V_{H_2O} ^{added}=5.18L-0.895L=4.285L

Of diluent water.

Regards!

6 0
2 years ago
Why are earthquakes different in New Madrid than in California.
maw [93]
Well it depends how close the places are to the edges of tectonic plates. Also the damage caused from the Earthquakes has to do with how sturdy the buildings are and whether they were built to withhold such strong forces.
5 0
2 years ago
A brine solution of salt flows at a constant rate of 4L/min into a large tank that initially held 100L of pure water. The solutio
ella [17]

Answer:

To reach 01.kg/L concentration of salt in the tank will take around 18.9 min

Explanation:

Attached

8 0
3 years ago
Read 2 more answers
2<br> 2NH3<br> N, + 3H.<br> O<br> 9 mol H, X<br> 2<br> =<br> C
MaRussiya [10]

Ummm...

WHat is this? What do you want us to do??

4 0
2 years ago
If the percentage yield is 92.0% how many grams of CH3OH can be made by reaction of 5.6 x 103g with 1.0 x 103 g
Marizza181 [45]
Answer is: 5888 grams of CH₃OH.
Chemical reaction: CO + 2H₂ → CH₃OH.
m(CO) = 5,6·10³ g = 5600 g.
m(H₂) = 1,0·10³ g = 1000 g.
n(CO) = 5600 g ÷ 28 g/mol
n(CO) = 200 mol, limited reactant.
n(H₂) = 1000 g ÷ 2 g/mol.
n(H₂) = 500 mol.
from reaction: n(CO) : n(CH₃OH) = 1 : 1.
n(CH₃OH) = n(CO) = 200 mol.
m(CH₃OH) = 200 mol · 32 g/mol · 0,92.
m(CH₃OH) = 5888 g.

5 0
3 years ago
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