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Ilia_Sergeevich [38]
4 years ago
6

Why do we use ammonium formate as a hydrogen surrogate instead of using hydrogen gas in this experiment?

Chemistry
1 answer:
NemiM [27]4 years ago
7 0

Answer:

Ammonium formate can also be used in palladium on carbon (Pd/C) reduction of functional groups. In the presence of Pd/C, ammonium formate decomposes to hydrogen, carbon dioxide, and ammonia.

Explanation:

This hydrogen gas is adsorbed onto the surface of the palladium metal, where it can react with various functional groups.

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Given the specific heat of lead is 0.129 J/gK and that it takes 93.45 of energy to heat a sample of lead from 22.3°C to 40.4°C f
gulaghasi [49]

Answer:

nice

Explanation:

you can do it just try your best

5 0
2 years ago
Marble(calcium carbonate) reacts with hydrochloric acid(hcl) to form calcium chloride solution, water, and carbon dioxide. Find
Leni [432]

Answer:

When calcium carbonate reacts with hydrogen chloride, it reacts to form calcium chloride, carbon dioxide, and water. If this reaction occurs with 51.6% yield, what mass of carbon dioxide will be collected if 16.93 g of CaCO3 is added to sufficient hydrogen chloride

3 0
3 years ago
What is the percent by mass of 54.7g of calcium chloride dissolved in 500g of water?
Advocard [28]
% by mass = (mass solute/mass solution)*100%
mass  of the solute = 54.7 g
mass of the solution = mass solute + mass solvent=54.7+500=554.7 g
% by mass = (54.7/554.7)*100%≈0.0986*100% = 9.86%

3 0
4 years ago
If an individual proton has mass 1.007825 amu, and an individual neutron has mass 1.008665 amu, what's the calculated mass of a
german

Answer:

C) 237.96682 amu

Explanation:

The symbol for neptunium-236 is given as;

²³⁶₉₃Np

This element has 93 protons and (236 - 93 = 143) neutrons.

Mass Number =Total mass of Protons + Total mass of neutrons

Total Mass pf protons = 93 * 1.007825 amu, = 93.727725 amu

Total mass of Neutrons = 143 * 1.008665 amu = 144.239095 amu

Mass = 144.239095 + 93.727725  = 237.96682 amu

Correct option is option C.

7 0
3 years ago
How much energy is released when 65.8 g of water freezes
Delvig [45]

The amount of energy released is calculated by the product of heat of fusion and mass. The formula of amount energy released is given by: q= L\times m                (1)

Here,  

q is amount of energy released L is heat of fusion (334 J/g) m is mass of water Put all the given values in equation (1)

q= 334 J/g \times 65.8 g

q= 21977.2 Joules ≅ 21977 Joules

q= 21977 Joules

Thus, amount of energy released is 21977 Joules


6 0
3 years ago
Read 2 more answers
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