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vovikov84 [41]
3 years ago
11

Calculate the Ph of:

Chemistry
1 answer:
andrey2020 [161]3 years ago
4 0

Answer:

pH= 3.82

Explanation:

Sodium ethanoate or sodium acetate (CH3COONa) ionises completely.

Ethanoic acid or acetic acid (CH3COOH), ionises partially because it is a weak acid.

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Iron and oxygen react together to make iron (III) oxide (rust). You know that this is a chemical reaction and not a nuclear reac
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The atoms didn't change we only added 2 different ones together. 2nd one is right
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3 years ago
Read 2 more answers
determine the frequency and wavelength (in nm) of the light emitted when the e- fell from n=4 and n=2
Lostsunrise [7]

Answer:

Frequency = 6.16 ×10¹⁴ Hz

λ = 4.87×10² nm

Explanation:

In case of hydrogen atom energy associated with nth state is,

En =  -13.6/n²

For n = 2

E₂ = -13.6 / 2²

E₂ = -13.6/4

E₂ = -3.4 ev

Kinetic energy of electron = -E₂ = 3.4 ev

For n = 4

E₄ = -13.6 / 4²

E₄ = -13.6/16

E₄ = -0.85 ev

Kinetic energy of electron = -E₄ = 0.85 ev

Wavelength of radiation emitted:

E = hc/λ = E₄ - E₂

hc/λ = E₄ - E₂

by putting values,

6.63×10⁻³⁴Js × 3×10⁸m/s / λ = -0.85ev   - (-3.4ev )

6.63×10⁻³⁴ Js× 3×10⁸m/s / λ = 2.55 ev

λ = 6.63×10⁻³⁴ Js× 3×10⁸m/s  /2.55ev

λ = 6.63×10⁻³⁴ Js× 3×10⁸m/s  /2.55× 1.6×10⁻¹⁹ J

λ = 19.89 ×10⁻²⁶ Jm / 2.55× 1.6×10⁻¹⁹ J

λ = 19.89 ×10⁻²⁶ Jm / 4.08×10⁻¹⁹ J

λ = 4.87×10⁻⁷ m

m to nm:

4.87×10⁻⁷ m ×10⁹nm/1 m

4.87×10² nm

Frequency:

Frequency = speed of electron / wavelength

by putting values,

Frequency = 3×10⁸m/s /4.87×10⁻⁷ m

Frequency = 6.16 ×10¹⁴ s⁻¹

s⁻¹ = Hz

Frequency = 6.16 ×10¹⁴ Hz

3 0
3 years ago
What is the main reason that the bounce height decrease.
tiny-mole [99]
Since there is loss of kinetic energy
5 0
3 years ago
Confused as heck. please help!
Nitella [24]

Answer: that all thre water cycle and C is vaporation

Explanation:

6 0
2 years ago
Which statement best describes how two hydrogen atoms combine to form molecular hydrogen (H2)?
dimaraw [331]
Nope, its A i just took the test
<span>Two neutral hydrogen atoms share electrons in a covalent bond.
</span>
8 0
3 years ago
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