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swat32
3 years ago
8

What are forces like in a collision?

Physics
1 answer:
andre [41]3 years ago
3 0

Answer:

equal in magnitude and opposite in direction.

Explanation:

I don't have 1 I just knew -_('-')_-

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Use Percentages Given that the molecular mass of magnesium
ira [324]

Answer:

27%

Explanation:

15.999 divided by 58.32 = .27433128

Move the decimal place over 2 places.

27%

5 0
4 years ago
Which interaction of nature is weakest?
LekaFEV [45]
Electromagnetic would be the weakest interaction of nature.
5 0
3 years ago
Complete the following:
masha68 [24]

When light is incident parallel to the principal axis and then strikes a lens, the light will refract through the focal point on the opposite side of the lens.

To find the answer, we have to know about the rules followed by drawing ray-diagram.

<h3>What are the rules obeyed by light rays?</h3>
  • If the incident ray is parallel to the principal axis, the refracted ray will pass through the opposite side's focus.
  • The refracted ray becomes parallel to the major axis if the incident ray passes through the focus.
  • The refracted ray follows the same path if the incident light passes through the center of the curve.

Thus, we can conclude that, when light is incident parallel to the principal axis and then strikes a lens, the light will refract through the focal point on the opposite side of the lens.

Learn more about refraction by a lens here:

brainly.com/question/13095658

#SPJ1

8 0
2 years ago
An electron has a charge of - 1.6x10 ^ - 19 C and a proton has a charge of 1.6x 10 ^ - 19 C . In a hydrogen atom, the distance b
ra1l [238]

Answer:, , 8.2 . 10^-6, ATTRACTIVE

Explanation:

The magnitude of the electrostatic force between two charges is given by Coulomb's law

4 0
3 years ago
Two loops of wire are arranged so that a changing current in one will induce a current in the other. If the current in the first
patriot [66]

Answer:

The current in the second loop will stay constant

Explanation:

Since the induced emf in the second coil, ε due to the changing current i₁ in the first wire loop ε = -Mdi₁/dt where M = mutual inductance of the coils and di₁/dt = rate of change of current in the first coil = + 1 A/s (positive since it is clockwise)

Now ε = i₂R where i₂ = current in second wire loop and R = resistance of second wire loop.

So,  i₂R = -Mdi₁/dt

i₂ = -Mdi₁/dt/R

Since di₁/dt = + 1 A/s,

i₂ = -Mdi₁/dt/R

i₂ = -M × + 1 A/s/R

i₂ = -M/R

Since M and R are constant, this implies that i₂ = constant

<u>So, the current in the second wire loop will stay constant.</u>

3 0
3 years ago
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