Question

A 2.0 sample of N2 occupy 50.0L at 15 degrees Celsius and 640mmHg. What volume will the gas occupy at 45 degrees Celsius and 160mmHg?

Answer 1

Answer:

220.8L

Explanation:

Given parameters:

Initial volume  = 50L

Initial temperature = 15°C  = 288K

Initial pressure = 640mmHg

Final temperature  = 45°C  = 318K

Final pressure  = 160mmHg

Unknown:

Final volume  = ?

Solution:

Using the combined law;

        $\frac{p_{1}v_{1} }{T_{1} }$  = $\frac{p_{2}v_{2} }{T_{2} }$  

p,v and T are pressure, volume and Temperature

    $\frac{640 x 50}{288}$  = $\frac{160 x v_{2} }{318}$

     160 x 288 x v₂ = 640 x 50 x 318

                         v₂ = 220.8L