Answer:
The molarity of acid is 3 M.
Explanation:
Given data:
Volume of H₃PO₄ = 25 mL
Volume of NaOH = 50 mL
Molarity of NaOH = 1.50 M
Molarity of H₃PO₄ = ?
Solution:
Formula:
M₁V₁ = M₂V₂
M₁ = M₂V₂ / V₁
M₁ = 1.50 M ×50 mL / 25 mL
M₁ = 75 M. mL / 25 mL
M₁ = 3 M
The molarity of acid is 3 M.
What following?? Conditions??
<u>Answer:</u> The volume of isopropyl alcohol present is 254.4 mL and the volume of water present is 540.6 mL
<u>Explanation:</u>
We are given:
32.0 % (v/v) alcohol solution
This means that 32 mL of isopropyl alcohol is present in 100 mL of solution
Volume of water = 100 - 32 = 68 mL
Volume of solution given = 795 mL
Applying unitary method:
In 100 mL of solution, the volume of isopropyl alcohol present is 32 mL
So, in 795 mL of solution, the volume of isopropyl alcohol present will be = 
Volume of water in given amount of solution = 795 - 254.4 = 540.6 mL
Hence, the volume of isopropyl alcohol present is 254.4 mL and the volume of water present is 540.6 mL
The statements which correctly describe the Cl-Cl bond is:
It is a sigma bond.
It is formed by overlap of two hybrid orbitals.
Explanation:
The 2 atoms of the chlorine atom are bonded by single bond by sharing of electrons as chlorine has 7 electrons in its outer shell.
1s22s2p63s23p5 configuration of each atom
A covalent bond is formed between the two chlorine atoms.
The electrons are shared by molecular orbitals by overlapping the orbital as each of the chlorine atom will try to complete its octet. The electrons from p orbitals are shared hence sigma bond.
There is no hybridization in Cl2 it only has only overlapping of electrons in p orbitals.
