Answer:
At the same rate 18 carburetors out of 1,050 could be expected to be detective.
Step-by-step explanation:
The number of carburetors tested = 175
Defective pieces out o f 175 = 3
So, ratio of defected to tested = 3 : 175
Now, the number of carburetors tested in second batch = 1,050
Here, let the defective pieces = m
So, by the Ratio of Proportion,
or, 
⇒ m = 18
Hence, at the same rate 18 carburetors out of 1,050 could be expected to be detective.
I've attached the complete question.
Answer:
Only participant 1 is not cheating while the rest are cheating.
Because only participant 1 has a z-score that falls within the 95% confidence interval.
Step-by-step explanation:
We are given;
Mean; μ = 3.3
Standard deviation; s = 1
Participant 1: X = 4
Participant 2: X = 6
Participant 3: X = 7
Participant 4: X = 0
Z - score for participant 1:
z = (x - μ)/s
z = (4 - 3.3)/1
z = 0.7
Z-score for participant 2;
z = (6 - 3.3)/1
z = 2.7
Z-score for participant 3;
z = (7 - 3.3)/1
z = 3.7
Z-score for participant 4;
z = (0 - 3.3)/1
z = -3.3
Now from tables, the z-score value for confidence interval of 95% is between -1.96 and 1.96
Now, from all the participants z-score only participant 1 has a z-score that falls within the 95% confidence interval.
Thus, only participant 1 is not cheating while the rest are cheating.
Answer:
$440
Step-by-step explanation:
notes $2 - n
notes $10 - m
n + m = 80 ----------> m = 80 - n
1 - 2/5 = 3/5
45 * $2 + 35 * $10 = 90 + 350 = $440
