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marishachu [46]
3 years ago
10

Statistical time division multiplexing does not require the capacity of the circuit to be equal to the sum of the combined circu

its. True False
Physics
1 answer:
aleksklad [387]3 years ago
7 0

Answer:

The answer is True

Explanation:

Statistical Multiplexing is considered an example of communication link sharing which makes it comparable to DBA (Dynamic Bandwidth Allocation). Here, communication channels are broken down into data streams to optimize the communication process.

In Statistical Time-division Multiplexing, time slots are allocated to data streams for communication optimization. This method makes sure that no time slot or bandwidth is wasted.

Hence, the sum of combined circuits must not be equal to the capacity of the circuit to work effectively.

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A long string carries the wave; a segment of the string measuring 6.00 meters in length and weighing 180 grams contains four full wavelengths. The string vibrates sinusoidally at a 50.0 Hz frequency with a 15.0 cm peak-to-valley displacement. The vertical distance between the farthest positive and negative positions is known as the "peak-to-valley" distance. The function that describes this wave traveling in the positive x direction is y=(7.50 \mathrm{~cm}) \sin \left(\frac{4 \pi}{3} \times-314 t+\phi\right).

\begin{aligned}& f=500 \mathrm{~Hz} \\&\mu=\frac{180 \times 10^{-3}}{6}=3 \times 10^{-2} K g / m \\&2 A=15 \times 10^{-2} m \\&A=7.5 \times 10^{-2} m \\&4 \lambda=6, \lambda=3 / 2 m \text {. and } v=f \lambda=75 m / \mathrm{sec} \\&\omega=2 \pi f=100 \pi \text { also } K=\frac{\omega}{v}=\frac{4 \pi}{3}\end{aligned}

If phase constant is $\phi$ then

$\therefore$ equation is $y=7.5 \times 10^{-2} \sin \left[100 \pi t-\frac{4 \pi}{3} x+\phi\right]$

∴ equation is y=(7.50 \mathrm{~cm}) \sin \left(\frac{4 \pi}{3} \times-314 t+\phi\right)

  • A wave is a disturbance that moves from one location to another, carrying energy but not always matter.
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To know more about Wave functions visit : brainly.com/question/3639648

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