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Stella [2.4K]
3 years ago
12

In ΔXYZ, ∠Y=90° and ∠X=73°. ∠ZWY=80° and XW=80. Find the length of ZY to the nearest 100th.

Mathematics
1 answer:
lawyer [7]3 years ago
8 0

Answer:

Solution given:

Y=90°

∠X=73°.

∠ZWY=80°

and XW=80.

ZY=?

We know that

In right angled triangle ∆ XYZ

Tan 73=\frac{p}{h}

3.27=\frac{yz}{xy}

3.27×[xy]=yz

xw+wy=\frac{yz}{3.27}

wy=\frac{yz}{3.27}-80...........(1)

again

In right angled triangle WYZ

Tan 80=\frac{yz}{wy}

5.67×wy=yz

wy=\frac{yz}{5.67}

yz=5.67×wy............................................(2)

E<u>q</u><u>u</u><u>a</u><u>t</u><u>i</u><u>n</u><u>g</u><u> </u><u>equation</u><u> </u><u>1</u><u>&</u><u>2</u>

\frac{yz}{5.67}=\frac{yz}{3.27}-80

\frac{yz}{3.27}-\frac{yz}{5.67}=80

5.67yz-3.27yz=80*5.67*3.27

2.4yz =1483.272

yz=\frac{1483.272}{2.4}

yz=618.03

:.y=618.03unit.<u>the length of ZY to the nearest 100</u><u>th</u><u> </u><u>is</u><u> </u><u>6</u><u>1</u><u>8</u><u>.</u>

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