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Sergeeva-Olga [200]
3 years ago
6

How does the range of a ground launched projectile change when the launch angle changes?

Physics
2 answers:
Zepler [3.9K]3 years ago
8 0

Answer:

Higher launch angles have higher maximum height

Since steeper launch angles have a larger vertical velocity component, increasing the launch angle increases the maximum height.

adoni [48]3 years ago
6 0
What the person on top of me said
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A freight train car has a mass of 2,000 kilograms and an acceleration of 1.8 m/s/s. ​What is the average force behind that train
abruzzese [7]

Answer:

F = 3600 [N]

Explanation:

To solve this problem we must use Newton's second law, which tells us that the sum of force must be equal to the product of mass by acceleration.

ΣF = m*a

where:

F = force [N]

m = mass = 2000 [kg]

a = acceleration = 1.8 [m/s^2]

Now replacing:

F = 2000*1.8

F = 3600 [N]

8 0
4 years ago
What properties of the wave define why it is found within this area of the spectrum?
MatroZZZ [7]

Answer:

Explanation:

Speed and medium are properties of a wave which is in common within an area of the spectrum of visible light. i.e;

Their medium of propagation

They both travel at the same speed ( speed of light )

The properties mentioned above are properties that define that wave is found within an area spectrum for visible light.

Wish I Could Help You!

7 0
2 years ago
Landon's new toy arrived in the mail covered in foam packing peanuts. The foam packing peanuts have a mass of 30 g and a volume
gogolik [260]

The formula for calculating <em>density </em>is P=M/V where P is the <em>density</em>, M is the <em>mass</em>, and V is the <em>volume</em>.

The problem gives you the <em>mass</em>, 30g, and the <em>volume</em>, 60cm^3;you can plug those into the equation, which should give you P=30/60.

Your answer should end up being P=0.5 g/cm^3.


WORK:

P=M/V

P=30g/60cm^3

P=0.5g/cm^3

4 0
3 years ago
A 1.95 kg box sits on an incline of 24 ° with the horizontal. If the box accelerates down the incline at 0.245 m/s 2 , what is t
koban [17]

Answer:

Explanation:

                            F = ma

mgsinθ - μmgcosθ = ma

      gsinθ - μgcosθ = a

                   μgcosθ = gsinθ - a

                              μ = (gsinθ - a) / gcosθ

                              μ = (9.81sin24 - 0.245) / 9.81cos24

                              μ = 0.4178906...

                              μ = 0.418

6 0
3 years ago
a car accelerates from rest to a velocity of 5meters/second in 4 seconds. what is its average acceleration over this period of t
Pani-rosa [81]

Answer:

1.25 m/s²

Explanation:

Average acceleration is the change in velocity over change in time.

a = Δv / Δt

a = (5 m/s − 0 m/s) / 4 s

a = 1.25 m/s²

6 0
4 years ago
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