Answer:
<em><u>a) </u></em><em><u> </u></em><em><u>Carbonic acid</u></em>
<em><u>b</u></em><em><u>)</u></em><em><u> </u></em><em><u>ammonium hydroxide</u></em>
<em><u>c</u></em><em><u>)</u></em><em><u> </u></em><em><u>Aluminum phosphate</u></em>
<em><u>d</u></em><em><u>)</u></em><em><u> </u></em><em><u>Sodium hydroxide</u></em>
<em><u>e</u></em><em><u>)</u></em><em><u> </u></em><em><u>Gold trichloride</u></em>
Explanation:
<em>I</em><em> </em><em>hope this</em><em> </em><em>will help</em><em> </em><em>you</em><em> </em><em>buddy</em><em> </em>
Answer: The correct answer is an emission line spectrum.
Explanation:
When the electrons are excited to the higher energy level, the energy is absorbed in this case.
When the electrons in the atom step down to lower energy levels in a thin cloud of hot gas then the radiation will emit.
The electron will lose energy in this case in the form of radiation. There will be an emission line spectrum.
Answer:
The resulting force on the child is 3000 lbf
Explanation:
To find the force that acts on a child of 50 lb with a deceleration of 60 g's, we can use the formula:
Force = mass * acceleration
To find the force in lbf, we need to use the mass in lb and the acceleration in g (standard unit of gravity).
So we have that:
Force = 50 * 60
Force = 3000 lbf
So the resulting force on the child is 3000 lbf.
Answer:

Explanation:
Given:
mass of person, 
mass of merry go-round, 
radius of merry go-round, 
velocity of the person running, 
<u>We consider merry go-round as a ring:</u>
Now the moment of inertial of the ring is given as,



<u>Moment of inertia of the person considering as a point mass:</u>



<u>Now according to the conservation of angular momentum:</u>

where:
angular velocity of the merry-go-round
angular velocity of the person running


