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Firlakuza [10]
3 years ago
6

Why do you think that if you drop two balls, exactly two balls rise on the other side at a similar speed? Why doesn’t one ball f

ly off quickly instead? Why don’t three balls fly off slowly?
Physics
1 answer:
Zolol [24]3 years ago
7 0
It conserves both energy and momentum in the collision at the same time. By design, when the balls collide the strings that hold them up are vertical (assuming balls are only swung from one side).

: Hope this helps :)
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A car comes to a bridge during a storm and finds the bridge washed out. The driver must get to the other side, so he decides to
Verizon [17]

Answer:29.41 m/s

Explanation:

Given

Height of cliff 22.8 m

Height of river bank=2.4 m

width of river=60.0 m

Car can considered as projectile

Time travel to cover vertical distance=22.8-2.4=20.4 m

h=ut+\frac{at^2}{2}

20.4=0+\frac{gt^2}{2}

t^2=4.163

t=2.04 s

Range=60 m

Let u be the speed of car

ut=60

u=\frac{60}{2.04}=29.41 m/s

4 0
3 years ago
Select the correct answer.
Triss [41]

Answer:

Jim's kinetic energy is 54.67 J.

Explanation:

Given that,

Mass, m = 15 kg

Velocity, V = 2.7 m/s

We need to find the Jim's kinetic energy. We know that when the object is in motion, it has kinetic energy. This energy is given by :

E=\dfrac{1}{2}mv^2

E=\dfrac{1}{2}\times 15\ kg\times (2.7\ m/s)^2

E = 54.67 J

So, Jim's kinetic energy is 54.67 J. Hence, this is the required solution.

5 0
3 years ago
Please help.
Alex787 [66]

Explanation:

<em>math</em><em>ematically</em><em>,</em>

<em>kinetic \: energy \:  =  \frac{1}{2} m {v}^{2}</em>

<em>wher</em><em>e</em><em> </em><em>m</em><em>=</em><em> </em><em>mass</em>

<em>and</em><em> </em><em>v</em><em>=</em><em>veloc</em><em>ity</em>

<em>giv</em><em>en</em><em> </em><em>that</em><em>,</em><em> </em>

<em>kinet</em><em>ic</em><em> energy</em><em>=</em><em>4</em><em>9</em><em>3</em><em>9</em><em>0</em><em>0</em><em>J</em>

<em>mass</em><em> </em><em>=</em><em>5</em><em>0</em><em>4</em><em>0</em><em>k</em><em>g</em>

<em>maki</em><em>ng</em><em> </em><em>velo</em><em>city</em><em> </em><em>the</em><em> </em><em>su</em><em>bject</em>

<em>v =  \sqrt{ \frac{2 \times kinetic \: energy}{mass} }</em>

<em>sub</em><em>stitute</em><em> </em><em>the</em><em>ir</em><em> </em><em>valu</em><em>es</em><em> </em><em>in</em><em> </em><em>the</em><em> </em><em>formu</em><em>la</em>

<em>v =  \sqrt{ \frac{2 \times 493900}{5040} }</em>

<em>v =  \sqrt{ \frac{987800}{5040} }</em>

<em>v =  \sqrt{196}</em>

<em>v = 14m {s}^{ - 1}</em>

<em>Thu</em><em>s</em><em> </em><em>th</em><em>e</em><em> </em><em>velo</em><em>city</em><em> </em><em>is</em><em> </em><em>1</em><em>4</em><em>m</em><em>e</em><em>t</em><em>e</em><em>r</em><em>s</em><em> </em><em>per</em><em> </em><em>se</em><em>cond</em>

6 0
3 years ago
How is frequency related to period?
zhannawk [14.2K]

Answer:

A

Explanation:

A

3 0
3 years ago
You’ve been given the challenge of balancing a uniform, rigid meter-stick with mass M = 95 g on a pivot. Stacked on the 0-cm end
Mariulka [41]

Answer: d = 4750n/3.1+95n

Explanation:

Using the principle of moment to solve the question.

Sum of clockwise moments = sum of anti clockwise moments

Since there are n identical coins with mass 3.1g placed at point 0cm, 1 coin will have mass of 3.1/n grams

Taking moment about the pivot,

Mass 3.1/n grams will move anti-clockwisely while the mass 95g will move in the clockwise direction.

Since its a meter rule (100cm) the distance from the center mass(95g) to the pivot will be 50-d (check attachment for diagram).

To get 'd'

We have 3.1/n × d = 95 × (50-d)

3.1d/n = 4750-95d

3.1d = 4750n-95dn

3.1d+95dn=4750n

d(3.1+95n) = 4750n

d = 4750n/3.1+95n

6 0
4 years ago
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