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Ugo [173]
3 years ago
6

Hi, so i have to find T1, can some1 help?

Physics
1 answer:
iragen [17]3 years ago
7 0

30.1 N

Explanation:

Given:

W_1 = 16\:\text{N}

W_2 = 8\:\text{N}

Let's write the components of the net forces at the intersections. Note that the system is equilibrium so all the net forces are zero.

<u>Forces</u><u> </u><u>involving</u><u> </u><u>W1</u><u>:</u>

x:\:\:\:-T_1 + T_3\cos \alpha = 0\:\: \\ \text{or}\:\:T_2 = T_3\cos \alpha\:\:\:\:\:(1)

y:\:\:\:T_3\sin \alpha - W_1 = 0\:\:\: \\ \text{or}\:\:\:T_3\sin \alpha = W_1\:\:\:\:\:\:(2)

<u>Forces</u><u> </u><u>involving</u><u> </u><u>W2</u><u>:</u>

x:\:\:\:T_1\sin 53 - T_3\sin \alpha = W_2\:\:\:\:\:\:\:(3)

y:\:\:\:T_4 - T_1\cos 53 - T_3\cos \alpha = 0\:\:\:\;(4)

Substitute (2) into (3) and we get

T_1\sin 53 - W_1 = W_2

Solving for T_1,

T_1 = \dfrac{W_1 + W_2}{\sin 53} = 30.1\:\text{N}

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Answer:

10.16 degrees

Explanation:

Apply Snells Law for both wavelenghts

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For red, the angle is 35.45degrees

For violet

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For violet, the angle is 45.6 degrees

The difference is 45.6- 35.45 = 10.16 degrees

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cuz its informing the length of 5 and weight on 20N

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PLEASE HELP ASAP...TIMED TEST. PLEASE ANSWER WITH AT LEAST A PARAGRAPH!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
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The best I could do.

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3 years ago
How does the time at which you see things happen at a baseball game compare to the time when you hear things happen? Explain you
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Answer:

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The first thing that happens in such cases is to take into account the speed of the sound. First, we see that the player hits the ball with the bat, if we are in the stands far enough we will hear the sound of the batting time later, this time depends on the speed of the sound which is equal to 345 [m/s].

Another visible and practical example is a fireworks display, where people nearby immediately hear the explosion. while those at a great distance will be able to see first the explosion followed by the sound.

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In one of the classic nuclear physics experiments at the beginning of the 20th century, an alpha particle was accelerated toward
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Answer:

The answer is "1.01 \times 10^{-13}"

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\to r=\frac{kqq'}{KE}\\\\

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5 0
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