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2 years ago

HURYY PLEASE

Physics

2 answers:

goldfiish [28.3K]2 years ago

6 0

Answer:

the flow i belive im doing it on my astravo!

Explanation:

-BARSIC- [3]2 years ago

4 0

The flow in systems besides the flow

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On a vacation flight, you look out the window of the jet and wonder about the forces exerted on the window. Suppose the air outs

user100 [1]

Answer:

A) $\Delta P = 14512.5 Pa = 14.512 kPa$

B) F = 1632.65 N

Explanation:

Given details

outside air speed is given as $v_2 = 150 m/s$

since inside air is atmospheric , $v_1 = 0 m/s$

a) By using bernoulli equation between outside and inside of flight

$P_1 + \frac{1}{2} \rho v_1^2 + \rho gh = P_2 + \frac{1}{2} \rho v_2^2 + \rho gh$

$\Delta P = \frac{1}{2} \rho v_2^2 - \frac{1}{2} \rho v_1^2$

$\Delta P = \frac{1}{2} \rho[ v_2^2 -v_1^2]$

$\Delta P = \frac{1}{2} 1.29 [ 150^2 - 0^2]$

$\Delta P = 14512.5 Pa = 14.512 kPa$

b) force exerted on window

Area of window $= 25\times 45 = 1125 cm^2 = 0.1125 m^2$

We know that force is given as

$F = P\times A$

$F = 14512.5 \times 0.1125$

F = 1632.65 N

5 0

3 years ago

A fly enters through an open window and zooms around the room. In a Cartesian coordinate system with three axes along three edge

AnnyKZ [126]

Answer:

Explanation:

Displacement vector along x axes = 4.5 - 2.5 = 2 m

Displacement vector along y axes = 3 - 2 = 1 m

Displacement vector along z axis = 3.5- 4 = - 0.5 m

Displacement vector = 2 i + j - 0.5 k m

7 0

3 years ago

A charged particle enters into a uniform magnetic field such that its velocity vector is perpendicular to the magnetic field vec

Phoenix [80]

Answer:

The particle path will follow

(d) a circular path

Explanation:

When a charged particle having charge of magnitude ' $q$ ' enters into a magnetic field such that its velocity vector ' $\vec{V}$ ' is perpendicular to the direction of the magnetic field ' $\vec{B}$ ', then it will experience a force, called Lorentz force ( $\vec{F_{L}}$ ), given by

$\vec{F_{L}} = \vec{V} \times \vec{B}$

As shown in the figure, the magnetic field is directed perpendicular to the plane and towards the plane (as shown by the circle and 'X'-sign) and the velocity vector is from left to right on the plane.

According to the property of cross-product, the Lorentz force ( $F_{L}$ ) acting on the particle will be perpendicular to the instantaneous position of the particle, making the path of the particle to be a circular path,as shown in the figure.