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Bezzdna [24]
2 years ago
9

How many grams of MgCl2 would be needed to make 5.3 liters of a 0.25 molar solution? Round your answer to the nearest 0.01,

Chemistry
1 answer:
GuDViN [60]2 years ago
6 0

Answer: 126.1 grams of are needed to make 5.3 L of 0.25 M solution

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

To calculate the mass of solute for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{given mass of solute}}{\text {Molar mass of solute}\times \text{Volume of solution in L}}

0.25M=\frac{x}{95.2g/mol\times 5.3L}

x=126.1g

Thus 126.1 grams of are needed to make 5.3 L of 0.25 M solution

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Serggg [28]

Explanation:

From your information above, assume 1 month is 28 days

1 days=24hours ; 28 days=672 hours (just multiply 1 days with 28)

1 hour=60minutes ; 672 hours=40,320 minutes

.. 1 month=40,320 minutes

5 0
2 years ago
Explain in terms of bonding why the hydrocarbon 2-methylpropane is saturated
lakkis [162]

Answer:

because no 2 or 3 bond so it is saturated

7 0
3 years ago
If you can continue to add more solute to a solution, the solution is said to be ____________________
Savatey [412]

Answer:

Unsaturated

Explanation:

In order to successfully answer this question, we need to think about the solubility of solutes in specific solvents, typically water.

  • A solution is considered to be unsaturated if at a given temperature and volume of water we may still add more solute and it will dissolve;
  • A solution is considered to be saturated if at a given temperature and volume of water we have a maximum amount of solute dissolved and trying to add more solute results in undissolved crystals that can be seen in the solution;
  • A solution is considered to be oversaturated (or supersaturated) i at a given temperature and volume of water we exceeded the maximum amount of a solute that could possibly dissolve.

In this case, if we can continue to add more solute to a solution and the solute dissolves, we may state that we are still at a point in which we have an unsaturated solution.

4 0
3 years ago
Read 2 more answers
Extend the aufbau sequence through an element that has not yet been identified, but whose atoms would completely fill 7p orbital
Thepotemich [5.8K]

Answer:

<u>Number of electrons</u> = 118

<u>Electronic configuration</u>: [Rn] 5f¹⁴ 6d¹⁰ 7s² 7p⁶

Explanation:

Given: A chemical element that has completely filled 7p orbital.

According to this, the principal occupied electron shell or the <u>valence shell of such an element is 7p.</u>

⇒ the principal quantum number <u>(n) for the valence shell is 7.</u>

∴ this element belongs to the period 7 of the periodic table.

Also, an element that has completely filled p-orbital belongs to the group 18 of the p-block.

Therefore, an element that belongs to the group 7 and period 18 of the periodic table, should have a <u>completely filled 5f, 6d, 7s and 7p orbitals</u>.

Therefore, the electronic configuration should be: [Rn] 5f¹⁴ 6d¹⁰ 7s² 7p⁶

And, the <u>number of electrons</u> = atomic number of radon (Rn) + 14 + 10 + 2 + 6 = 86 + 32 = <u>118</u>.

<u>Therefore, the given element has atomic number 118 and has the electronic configuration: [Rn] 5f¹⁴ 6d¹⁰ 7s² 7p⁶. Thus the given element can be Oganesson.</u>

7 0
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Which is an example of a building block that helps form DNA? cytosine polypeptide ribose uracil
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<span>Cytosine is a building block of DNA,
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7 0
3 years ago
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