How many grams of MgCl2 would be needed to make 5.3 liters of a 0.25 molar solution? Round your answer to the nearest 0.01,
1 answer:
Answer: 126.1 grams of are needed to make 5.3 L of 0.25 M solution
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.
To calculate the mass of solute for given molarity, we use the equation:
Thus 126.1 grams of are needed to make 5.3 L of 0.25 M solution
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24.25 moles of NO can be produced using 97 moles of HNO3.
<h3>What is balanced chemical equation?</h3>Equal numbers of atoms from various elements are present in both the reactants and the products in balanced chemical equations. Varied elements' atom counts in the reactants and products of unbalanced chemical equations are different.
3 Cu + 8HNO3 g → 3 Cu(NO3)2 + 2 NO + 4 H2O
The number of moles consumed can be calculated using comparing with coefficients in the balanced reaction .
So , from above eq we get that 8 moles of HNO3 are consumed to make 2 moles of NO.
⇒ 8 HNO3⇔2 NO
⇒ 1 HNO3⇔ 1/4 NO
This means that for each mole of HNO3 produces 1/4 moles of NO.
So , for 97 moles of HNO3 , moles of NO can be made,
So, total moles of NO made are 24.25 moles.
Lean more about balanced reactions here brainly.com/question/26694427
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