Answer:
(5,2,2)
Step-by-step explanation:
-3x+4y+2z = -3
2x-4y-z=0
y = 3x-13
Multiply the second equation by 2
2*(2x-4y-z)=0*2
4x -8y -2z =0
Add this to the first equation to eliminate z
-3x+4y+2z = -3
4x -8y -2z =0
-------------------------
x -4y = -3
Take the third equation and substitute it in for y
x - 4(3x-13) = -3
Distribute the 4
x - 12x +52 = -3
Combine like terms
-11x +52 = -3
Subtract 52 from each side
-11x +52-52 = -3-52
-11x = -55
Divide by -11
-11x/-11 = -55/-11
x=5
Now we can solve for y
y =3x-13
y =3*5 -13
y = 15-13
y=2
Now we need to find z
2x-4y-z=0
2(5) -4(2) -z=0
10-8 -z=0
2-z=0
Add z to each side
2-z+z= 0+z
2=z
x=5, y=2, z=2
(5,2,2)
B^2=9^2
9^2=81.
81 = answer
Answer:
option A and E
Step-by-step explanation:
Option A is equivalent because of the commutative law of addition;
(A + B) + C = A + (B + C)
option E is also correct because multiplication rule of inside the brackets.
A - ( - B - C) = A + B + C
SIN(x) = .7547
X = INVERSE-SIN(.7547)
X = 49.0 degrees
The given function is

The general form of the cosine function is

a is the amplitude
2pi/b is the period
c is the phase shift
d is the vertical shift
By comparing the two functions
a = 4
b = pi
c = 0
d = 1
Then its period is

The equation of the midline is

Since the maximum is at the greatest value of cos, which is 1, then

Since the minimum is at the smallest value of cos, which is -1, then

Then substitute them in the equation of the midline

The answers are:
Period = 2
Equation of the midline is y = 1
Maximum = 5
Minimum = -3