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Ray Of Light [21]
3 years ago
7

The first active volcano observed outside the Earth was discovered in 1979 on Io, one of the moons of Jupiter. The volcano was o

bserved to be ejecting material to a height of about 3.00 E5 m. Given that the acceleration of gravity on Io is 1.80 m/s2, find the initial velocity of the ejected material.
Physics
1 answer:
meriva3 years ago
8 0

Answer:

1039.23 m/s

Explanation:

Given:

Height, H = 3 x 10⁵m

acceleration of gravity on lo, a = 1.80 m/s² toward moon's surface i.e -1.80m/s² with respect to the earth

Now, at its highest point the velocity i.e the final velocity 'v' = 0m/s.

Now using the Newton's equation of motion

v² - u² =2as

where,

v = final velocity

u = initial velocity

a = acceleration

s = distance

now,

substituting the values we get

0²-u² = 2 × (-1.80) × 3 x 10⁵

or

u=\sqrt{10.8\times 10^5}=1039.23m/s

Hence, the <u>initial velocity</u><u> with which the material is ejected is </u><u>1039.23 m/s</u>

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A net force of 10 N accelerates an object at 5.0 m/s^2. What is the mass of the object? A. 2 kg B. 10 kg C. 5 kg D. 20 kg
Ludmilka [50]

Answer:

A. 2 kg

Explanation:

Force = 10N\\Acceleration = 5.0m/s^2\\Mass = ? = x\\Force = mass\times acceleration \\10 = x \times 5\\10 = 5x \\\frac{10}{5} =\frac{5x}{5} \\2=x\\\\Mass= 2kg

7 0
3 years ago
Janet jumps off a high diving platform with a horizontal velocity of 2.06 m/s and lands in the water 1.8 s later. How high is th
Archy [21]
Initial height of platform is 15.87m or 16m.

8 0
3 years ago
(I) A novice skier, starting from rest, slides down an icy frictionless 8.0° incline whose vertical height is 105 m. How fast is
Vlad1618 [11]

Answer:

v = 45.37 m/s

Explanation:

Given,

angle of inclination = 8.0°

Vertical height, H  = 105 m

Initial K.E. = 0 J

Initial P.E. = m g H

Final PE = 0 J

Final KE = \dfrac{1}{2}mv^2

Using Conservation of energy

KE_i + PE_i + KE_f + PE_f

0 + m g H = \dfrac{1}{2}mv^2 + 0

v = \sqrt{2gH}

v = \sqrt{2\times 9.8 \times 105}

v = 45.37 m/s

Hence, speed of the skier at the bottom is equal to v = 45.37 m/s

3 0
3 years ago
What is the energy of an electromagnetic wave that has a frequency of
sukhopar [10]

Answer:

Energy, \; E = 2.6504 * 10^{-34} \; Joules

Explanation:

Given the following data;

Frequency = 4.0 x 10⁹ Hz

Planck's constant, h = 6.626 x 10-34 J·s.

To find the energy of the electromagnetic wave;

Mathematically, the energy of an electromagnetic wave is given by the formula;

E = hf

Where;

E is the energy possessed by a wave.

h represents Planck's constant.

f is the frequency of a wave.

Substituting the values into the formula, we have;

Energy, \; E = 4.0 x 10^{9} * 6.626 x 10^{-34}

Energy, \; E = 2.6504 * 10^{-34} \; Joules

8 0
3 years ago
20. In a parallel RL circuit, 10 mA flows through the resistor and 4 mA flows through the inductor. What phase angle separates v
stellarik [79]

Answer:

Option D: 21.8 degrees

Explanation:

In a parallel RL circuit, the current in the resistor R and that in the inductor L are separated among themselves 90 degrees as illustrated in the attached image. In the image the current in the resistor is represented in orange, that of the inductor in blue, and the total current (vector addition of the previous two) is represented  in red, forming a certain angle (theta) with respect to the current in the resistor. The output voltage is the same as the input voltage as measured over the resistor R.

Therefore, the phase angle that separated output voltage and total current can be obtained using the fact that tan(phase angle) = \frac{I_l}{I_R} = \frac{x}{y} \frac{4}{10}, therefore the angle is the arctangent of 4/10:

arctang(\frac{4}{10} )= 21.801 degrees.

8 0
4 years ago
Read 2 more answers
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