The most interesting thing about this problem is that in order to use all of the given information, you need to ignore the laws of Physics, and never mind what the stone would really do if dropped from a real bridge in the real world.
Average velocity = (displacement) / (time for the displacement)
Displacement =
Straight path from the start point to the finish point = 45 meters down .
Time = 4.6 seconds
Average velocity = 45/4.6 = <em>9.783 meters/second down</em>
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In the real world, a dropped stone would only take 3.03 seconds
to fall 45 meters.
Alternatively, a stone that fell for 4.6 seconds from rest would fall
103.7 meters, with an average velocity of 22.5 meters/second down.
But we accepted the given information, and did the best we could do
with it.
Answer:
According to Newton's third law of motion to every action, there is an equal and opposite reaction. When a rocket moves in free space it ejects hot gases. ... It is then the “reaction force”. As a result, the rocket is accelerated or propelled in the opposite direction.
Launching a rocket relies on Newton's Third Law of Motion. A rocket engine produces thrust through action and reaction. The engine produces hot exhaust gases which flow out of the back of the engine. In reaction, a thrusting force is produced in the opposite reaction.
Answer:
a) 
b) 
Explanation:
given,
n =1.5 for glass surface
n = 1 for air
incidence angle = 45°
using Fresnel equation of reflectivity of S and P polarized light
using snell's law to calculate θ t
a) 
b) 
Answer: M = 6.13 × 10^18 kg
Explanation:
g = GM/r2,
Where
The mass M of the asteroid = ?
The radius r = 110000 m
g = 0.0338 m/s^2
G is the gravitational constant.
SI units its value is approximately 6.674×10^−11m3⋅kg−1⋅s−2
Using the formula
g = GM/r2
Cross multiply
GM = gr^2
6.674×10^-11M = 0.0338 × 110000^2
M = 408×10^6/6.674×10^-11
M = 6.13 × 10^18 kg
Answer:
Olympus Mons on Mars.
Explanation:
It was discovered on Mars in 1971 and stands at a monstrous 21.9 km.
For reference, Mount Everest stands at 8.8K.
