Answer:
24000 kg·m/s
Explanation:
Momentum is Mass x Velocity, so 1200 kg time 20 m/s = 24000 kg-ms/s
<span>v/2
This is an exercise in the conservation of momentum.
The collision specified is a non-elastic collision since the railroad cars didn't bounce away from each other. For the equations, I'll use the following variables.
r1 = momentum of railroad car 1
r2 = momentum of railroad car 2
x = velocity after collision
Prior to the collision, the momentum of the system was
r1 + r2
mv + m*0
So the total momentum is mv
After the collision, both cars move at the same velocity since it was non-elastic, so
r1 + r2
mx + mx
x(m + m)
x(2m)
And since the momentum has to match, we can set the equations equal to each other, so:
x(2m) = mv
x(2) = v
x = v/2
Therefore the speed immediately after collision was v/2</span>
Answer:
The ratio is
Explanation:
From the question we are told that
The period of the satellite is
Generally the period of earth around the sun is
Generally from Kepler's third law , which is mathematically represented as
Here is the radius of the orbit which the satellite rotate around the sun
is the radius of the orbit which the earth rotate around the sun
=>
=>
=>
=>
The answer would be false
In the Newtonian theory of gravitation, the effects of gravity are always attractive, and the resulting force is calculated with respect to the center of gravity of both objects. The law of universal gravitation formulated by Isaac Newton postulates that the force exerted by a point particle with mass M on another with mass m is directly proportional to the product of the masses (and the Universal Gravitation Constant), and inversely proportional to the square of the distance (r) that separates them:
Therefore the correct answer is 2.