It seems that some the work is already here, but I'd be glad to!! So for #3 which is 9x^2+15x, we can factor out both a 3 and an x (3x) so we know that 3x * 3x =9x^2 and 3x * 5 = 15x so once we take the 3x out of the equation, we are left with 3x(3x+5) and that's as far as you can factor.
For #4, we see that the common factor is 10m because 10m * 2n = 20mn and 10m * 3 = 30m so once we take 10m out of the original, it becomes 10m(2n-3)
For #5, this one the common factor is 4xy because 4xy * 2xy=8x^2y^2 and 4xy*x= 4x^2y and 4xy*3=12xy so once we take the 4xy out of the equation, it becomes 4xy(2xy-x-3)
Hope this helps!
This is the answer the x=3 and the y=2
Answer:
Perimeter = 12+4pi
Area = 16+8pi
Step-by-step explanation:
Description of the assumed shape:
A rectangle 2 x 8 superimposed on a semi-circle of radius 4.
Perimeter:
P = 2+8+2+(4)(pi) = 12+4pi
Area :
A = 2*8 +(pi)4^2/2 = 16 + 8pi
