Answer:
Catalase
Explanation:
These reactive oxygen specie or free radicals that cause damage or injury to cells also lead to oxidative stress if unchecked by antioxidants. As suggested in the question, there are several enzymes that act as antioxidants in mitigating the effects of these reactive oxygen specie or free radicals. These enzymes include catalase, superoxide dismutase and glutathiones (such as glutathione s-transferase).
The enzyme that however prevents the accumulation of hydrogen peroxide (H₂O₂) in the peroxisome is catalase. Catalase is an enzyme that is present in the peroxisome; it (catalase) detoxifies/acts on H₂O₂, converting it (H₂O₂) into water and oxygen.
Explanation:
c Silver is an excellent conductor
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Answer:
Final concentration of C at the end of the interval of 3s if its initial concentration was 3.0 M, is 3.06 M and if the initial concentration was 3.960 M, the concentration at the end of the interval is 4.02 M
Explanation:
4A + 3B ------> C + 2D
In the 3s interval, the rate of change of the reactant A is given as -0.08 M/s
The amount of A that has reacted at the end of 3 seconds will be
0.08 × 3 = 0.24 M
Assuming the volume of reacting vessel is constant, we can use number of moles and concentration in mol/L interchangeably in the stoichiometric balance.
From the chemical reaction,
4 moles of A gives 1 mole of C
0.24 M of reacted A will form (0.24 × 1)/4 M of C
Amount of C formed at the end of the 3s interval = 0.06 M
If the initial concentration of C was 3 M, the new concentration of C would be (3 + 0.06) = 3.06 M.
If the initial concentration of C was 3.96 M, the new concentration of C would be (3.96 + 0.06) = 4.02 M
<span>Zn⁰ + 2H⁺ ------> Zn²⁺ + H2⁰
H⁺ ion has oxidation number +1.
Zn²⁺ ion has oxidation number +2.
Atom of Zn has electric charge 0, and each hydrogen atom in the molecule H2 have oxidation number 0. So, </span> Zn and each hydrogen atom in H2 have oxidation numbers equals "0".<span>
</span><span>Answer is
D. Zn and each hydrogen atom in H2</span><span>
</span>
1 it a 2 it b 3 it c 4 it be 7 it a
