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Ostrovityanka [42]
3 years ago
12

Please help! im being timed!! urgent!

Physics
1 answer:
bogdanovich [222]3 years ago
5 0

Answer:

The answer is thermal energy

Explanation:

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Two everyday examples of a starting motion
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Pushing, pulling is the answer
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Ethanethiol (; also called ethyl mercaptan) is commonly added to natural gas to provide the ""rotten egg"" smell of a gas leak.
Tju [1.3M]

Answer:

S = 27500J / 308.15molK

Explanation:

Entropy measures the degree of disorganization of a system. It is measured in the entropy change that is equal to the heat exchanged divided by the temperature at which the process occurs.

S2-S1 = Q / T

S = entropy

Q = heat = 27.5 kJ / mol * 1000J / 1KJ = 27500J / mol

T = temperature = 35 + 273.15 = 308.15K

units = J / molK

S = 27500J / 308.15molK

3 0
3 years ago
What are the reactants
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Answer:

The reagents correspond to substances that react with others, generating a chemical reaction.

Explanation:

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H2 + 02 -> H202

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5 0
3 years ago
Why are you able to observe the Doppler effect on earth with sound waves but not with light waves?
VladimirAG [237]

Answer: When an ambulance passes with its siren blaring, you hear the pitch of the siren change: as it approaches, the siren’s pitch sounds higher than when it is moving away from you. This change is a common physical demonstration of the Doppler effect.

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6 0
3 years ago
You stand on a straight desert road at night and observe a vehicle approaching. This vehicle is equipped with two small headligh
spayn [35]

To solve this problem we will apply the concepts related to Reyleigh's criteria. Here the resolution of the eye is defined as 1.22 times the wavelength over the diameter of the eye. Mathematically this is,

\theta = \frac{1.22 \lambda }{D}

Here,

D is diameter of the eye

D = \frac{1.22 (539nm)}{5.11 mm}

D= 1.287*10^{-4}m

The angle that relates the distance between the lights and the distance to the lamp is given by,

Sin\theta = \frac{d}{L}

For small angle, sin\theta = \theta

sin \theta = \frac{d}{L}

Here,

d = Distance between lights

L = Distance from eye to lamp

For small angle sin \theta = \theta

Therefore,

L = \frac{d}{sin\theta}

L = \frac{0.691m}{1.287*10^{-4}}

L = 5367m

Therefore the distance is 5.367km.

4 0
3 years ago
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