Explanation:
Normal moles of
= volume × normal concentration
= 4.7 × 0.139 = 0.6533 mol
Moles of
in hyponatremia blood = volume × hyponatremia concentration
= 4.7 × 0.116 = 0.5452 mol
Moles of NaCl to be added = moles of extra
needed
= 0.6533 mol - 0.5452 mol = 0.1081 mol
Mass of NaCl = moles × molar mass of NaCl
= 0.1081 mol × 58.443
= 6.317g
= 6.32 g (approx)
Thus, we can conclude that mass of sodium chloride would need to be added to the blood is 6.32 g.
Answer: 2
Explanation: Greenhouse gases are very important in keeping our planet just right. If we have too many Greenhouse gases it would be too hot, but we can't eliminate all of them or it will be too cold
We are asked to convert 25 cg to units of hg.
1 cg = 1 centigram = 10⁻² g
1 hg = 1 hectogram = 10² g
The options given are:
a) 1 hg/ 10² g
b) 10² cg/ 1 hg
c) 10² hg/ 1 cg
d) 10⁻² g/ 1 cg
To convert 25 cg to 1 hg, we could convert the 25 cg to grams first, then grams to hg.
25 cg · 10⁻² g/ 1cg = 0.25 g
Here we have converted our number from cg to grams. We can use another conversion of grams to hg to complete the conversion.
0.25 g · 1 hg/ 10² g = 0.0025 hg
Therefore, the first conversion we used was d) 10⁻² g/ 1 cg.
Answer: The specific heat of the unknown metal is 
Explanation:
The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

Q = Heat absorbed=
Joules
m= mass of substance = 86.8 g
c = specific heat capacity = ?
Initial temperature of the water =
Final temperature of the water =
Change in temperature ,
Putting in the values, we get:


The specific heat of the unknown metal is 
<h2>Please mark me as brainliest please yaa!!!^_^</h2>