<h3>Answers are:
sine, tangent, cosecant, cotangent</h3>
Explanation:
On the unit circle we have some point (x,y) such that x = cos(theta) and y = sin(theta). The sine corresponds to the y coordinate of the point on the circle. Quadrant IV is below the x axis which explains why sine is negative here, since y < 0 here.
Since sine is negative, so is cosecant as this is the reciprocal of sine
csc = 1/sin
In quadrant IV, cosine is positive as x > 0 here. So the ratio tan = sin/cos is going to be negative. We have a negative over a positive when we divide.
Because tangent is negative, so is cotangent.
The only positive functions in Q4 are cosine and secant, which is because sec = 1/cos.
Answer:
x=64
Step-by-step explanation:
x=8
(x)^2=8^2
x=64
Hope it helps ;)
51 = 3k. We can switch this around to 3k = 51 (because it's easier for me)
3k = 51.
We divide by 3 on both sides to just get "k".
3k / 3 = 51 / 3
k = 17.
Answer:
your answer should be a
Step-by-step explanation:
Answer:
Pt. 1: D
Pt. 2: what are the options for part 2?
Step-by-step explanation: