The final velocity of the bullet+block is 0.799 m/s
Explanation:
We can solve this problem by applying the principle of conservation of momentum: in fact, the total momentum of the bullet-block system must be conserved before and after the collision.
Mathematically, we can write:
![mu+MU=(m+M)v](https://tex.z-dn.net/?f=mu%2BMU%3D%28m%2BM%29v)
where
m = 0.001 kg is the mass of the bullet
u = 800 m/s is the initial velocity of the bullet
M = 1 kg is the mass of the block
U = 0 is the initial velocity of the block (initially at rest)
v is the final combined velocity of the bullet and the block
Solving the equation for v, we find the final velocity:
![v=\frac{mu}{m+M}=\frac{(0.001)(800)}{0.001+1}=0.799 m/s](https://tex.z-dn.net/?f=v%3D%5Cfrac%7Bmu%7D%7Bm%2BM%7D%3D%5Cfrac%7B%280.001%29%28800%29%7D%7B0.001%2B1%7D%3D0.799%20m%2Fs)
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