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gulaghasi [49]
3 years ago
15

A horse pulls a wagon forward. What is the equal and opposite force for the force of the horse pushing down on the ground as des

cribed by Newton's third law
Physics
2 answers:
Ilya [14]3 years ago
7 0

Answer:

The equal and opposite force is equal to the sum of any frictional force to the product of the mass of the wagon and the acceleration of the wagon

Explanation:

Newton's third law states that for every action, or force, there is an equal and opposite reaction

The equal and opposite force = The mass of the Wagon, m × The acceleration of the wagon, a + Any frictional force present, F_f

Whereby the force with which the horse pulls the wagon = F, mathematically, we have;

The equal and opposite force = -F = m × a + F_f.

olga2289 [7]3 years ago
6 0

Answer:

Ground pushes up on the horse’s hooves

Explanation:

khan academy

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A force F at an angle θ above the horizontal is used to pull a heavy suitcase of weight mg a distance d along a level floor at c
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Answer:

option A

Explanation:

given,

Force = F

angle = θ

weight on suitcase = mg

distance = d

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Work done = ?

Work done is equal to force into displacement.

Friction act opposite to the force acting so, work done by frictional force will be negative.

frictional force will act into horizontal direction opposite to force.

here displacement is equal to d

now,

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Hence,the correct answer is option A

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At one point in the rescue operation, breakdown vehicle A is exerting a force of 4000 N and breakdown vehicle B is exerting a fo
lukranit [14]

Answer:

1.) Magnitude = 5596 N

2.) Direction = 60 degrees

Explanation: You are given that the breakdown vehicle A is exerting a force of 4000 N at angle 45 degree to the vertical and breakdown vehicle B is exerting a force of 2000 N

Let us resolve the two forces into X and Y component

Sum of the forces in the X - component will be 4000 × cos 45 = 2828.43 N

Sum of the forces in the Y - component will be 2000 + ( 4000 × sin 45 )

= 2000 + 2828.43

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The resultant force R will be

R = sqrt ( X^2 + Y^2 )

Substitutes the forces at X component and Y component into the formula

R = sqrt ( 2828.43^2 + 4828.43^2 )

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The direction will be

Tan Ø = Y/X

Substitute Y and X into the formula

Tan Ø = 4828.43 / 2828.43

Tan Ø = 1.707106

Ø = tan^-1( 1.707106 )

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Scientists have also proven that rocks and other sediments contained abundant amounts of trapped oxygen. Through time when the rocks have withered and formed into sediments these oxygen gases are released into the air and got trapped within the atmosphere overpowering the levels of carbon dioxide. 

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