A horse pulls a wagon forward. What is the equal and opposite force for the force of the horse pushing down on the ground as des
2 answers:
Answer:
The equal and opposite force is equal to the sum of any frictional force to the product of the mass of the wagon and the acceleration of the wagon
Explanation:
Newton's third law states that for every action, or force, there is an equal and opposite reaction
The equal and opposite force = The mass of the Wagon, m × The acceleration of the wagon, a + Any frictional force present,
Whereby the force with which the horse pulls the wagon = F, mathematically, we have;
The equal and opposite force = -F = m × a + .
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Answer:
-8.56V
Explanation:
Our values are given by,
e = 6.04 V
Φ = 30.3
VC = 5.32
We can calculate the voltage across the circuit with the emf formula, that is,
Now, Using Kirchoff Voltage Law,
Finally we have the potential difference across the inductor.
The car A has a mass of 1200 kg.
The car B has the mass of 1900 kg.
It is given that velocity of car A is given as 22 Km/hr
The car B has the velocity of 25 Km/hr.
Let the mass of two bodies are denoted as
Let the velocity of cars A and B are denoted as
The momentum before collision is-
[Here p stand for momentum.]
We are asked to calculate the final momentum of the system after collision.
The answer of the question is based law of conservation of linear momentum.
As per law of conservation of linear momentum the sum total linear momentum for an isolated system is always constant.Hence irrespective of the type of collision[elastic and inelastic],the momentum of the system is always constant which is a universal truth.
Let after the collision the velocity of A and B are
Hence the final momentum of the system is-
As per the law of conservation of linear momentum, the initial and final momentum must be equal i.e
Hence the option A is right.