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gulaghasi [49]
3 years ago
15

A horse pulls a wagon forward. What is the equal and opposite force for the force of the horse pushing down on the ground as des

cribed by Newton's third law
Physics
2 answers:
Ilya [14]3 years ago
7 0

Answer:

The equal and opposite force is equal to the sum of any frictional force to the product of the mass of the wagon and the acceleration of the wagon

Explanation:

Newton's third law states that for every action, or force, there is an equal and opposite reaction

The equal and opposite force = The mass of the Wagon, m × The acceleration of the wagon, a + Any frictional force present, F_f

Whereby the force with which the horse pulls the wagon = F, mathematically, we have;

The equal and opposite force = -F = m × a + F_f.

olga2289 [7]3 years ago
6 0

Answer:

Ground pushes up on the horse’s hooves

Explanation:

khan academy

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4 0
3 years ago
Carry's car has a mass of 1000 kg and its brakes can apply 8000 N of force. If she is driving at 24 m/s and sees something in th
-Dominant- [34]

3s

Explanation:

Given parameters:

Mass of car = 1000kg

Force applied = 8000N

speed = 24m/s

Unknown:

time taken for the car to stop = ?

Solution:

According to newton's second law of motion; "the force on a body is the product of its mass and acceleration".

  Force = mass x acceleration

  let us find the acceleration of the car;

     a = \frac{F}{M}  = \frac{8000}{1000}  = 8m/s²

since the car is accelerating at a rate of  8m/s², when the brakes are applied, it will start decelerating at the constant rate, - 8m/s²

Applying the appropriate equation of motion;

     V = U + at

V is the final velocity

U is the initial velocity

a is the acceleration

t is the time taken

        final velocity = 0

       0 = U + at

     -U = at

    -24 = -8t

         t = 3s

learn more:

Newton's laws brainly.com/question/11411375

#learnwithBrainly

8 0
4 years ago
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