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gulaghasi [49]
3 years ago
15

A horse pulls a wagon forward. What is the equal and opposite force for the force of the horse pushing down on the ground as des

cribed by Newton's third law
Physics
2 answers:
Ilya [14]3 years ago
7 0

Answer:

The equal and opposite force is equal to the sum of any frictional force to the product of the mass of the wagon and the acceleration of the wagon

Explanation:

Newton's third law states that for every action, or force, there is an equal and opposite reaction

The equal and opposite force = The mass of the Wagon, m × The acceleration of the wagon, a + Any frictional force present, F_f

Whereby the force with which the horse pulls the wagon = F, mathematically, we have;

The equal and opposite force = -F = m × a + F_f.

olga2289 [7]3 years ago
6 0

Answer:

Ground pushes up on the horse’s hooves

Explanation:

khan academy

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Help yet again :) A hockey player is skating on the ice at 15km/h. He shoots the puck at 138 km/h according to a radar gun on th
IceJOKER [234]

Answer:

speed of puck acc. to the radar gun = 138 km/h

speed of player = 15 km/h

since the player is in motion when he shoots, the speed of the puck will be the sum of the speed of the player and the speed at which he shot. so,

speed of puck = speed of player + speed of puck acc. to player

138 = 15 + speed of puck acc. to player

speed of puck acc. to player = 138 -15

speed of puck acc. to player = 123 km/h

Brainly this answer if you think it deserves it

7 0
3 years ago
A person driving her car at 48 km/h approaches an intersection just as the traffic light turns yellow. She knows that the yellow
trasher [3.6K]

Answer:

She must stop the car  before interception, distance traveled 12.66 m

Explanation:

We will take all units to the SI system

Vo = 48Km / h (1000m / 1Km) (1h / 3600s) = 13.33 m / s

V2 = 70 Km / h = 19.44 m / s

We calculate the distance traveled before stopping

X = Vo t + ½ to t²

Time is what it takes traffic light to turn red  is t = 2.0 s

X = 13.33 2 + 1.2 (-7) 2²

X = 12.66 m

It stops car before reaching the traffic light turning to red

Let's analyze what happens if you accelerate, let's calculate the acceleration of the vehicle

     V2 = Vo + a t2

      a = (V2-Vo) / t2

      a = (19.44-13.33) /6.6

      a = 0.926 m / s2

This is the acceleration to try to pass the interception, now let's calculate the distance it travels in the time the traffic light changes from yellow to red (t = 2.0 s)

X = Vo t + ½ to t²

X = 13.33 2 + ½ 0.926 2²

X = 28.58 m

Since the vehicle was 30 m away, the interception does not happen

4 0
3 years ago
A typical nuclear fission power plant produces about 1.00 GW of electrical power. Assume the plant has an overall efficiency of
mamaluj [8]

Answer:

mass consumed by 235U each day = 2 kg

Explanation:

electrical power produced = 1 GW = 1 × 10⁹ × (6.24151 × 10¹⁸ ) eV

                                            = 6.24151× 10²¹ MeV/s

thermal energy =  0.420 * 250 = 105 MeV

\dfrac{1 GW}{150 MeV}= \dfrac{6.24151\times 10^{21}}{105}

                                      = 5.94 × 10¹⁹ fission/second

                                       =5.94 × 10¹⁹× 24 × 60 ×60)

                                      =  5.13 × 10²⁴ fission/day

mu = 235.04393 ×  1.660× 10 ⁻²⁷ = 390.1729× 10⁻²⁷ Kg

M = mu ×5.13 × 10²⁴

   = 390.1729× 10⁻²⁷ ×5.13 × 10²⁴

M   =  2 kg(approx.)

mass consumed by 235U each day = 2 kg

3 0
3 years ago
The cost, density and resistivity of copper, steel and aluminum
otez555 [7]
Density of copper: 8,9
Density of steel: 7,7
Density of aluminum: 2,7
And
Resistivity of copper: 1,7
Resistivity of steel: 16,9
Resistivity of aluminum: <span>2,7</span>

Hope I Helped You!!! :-)

Have A Good Day!!!
3 0
3 years ago
A truck is using a hook to tow a car whose mass is one quarter that of the truck. If the force exerted by the truck on the car i
LenKa [72]

Answer:

Force exerted by car on truck will be 6000 N in opposite direction

Explanation:

It is given that mass of the car is one quarter of the mass of the truck

Force exerted by the truck on the car is 6000 N

We have to find the force exerted by car on the truck

According to newtons third law for any action there is equal and opposite reaction

So force exerted by car on the truck will be equal to 6000 N in opposite direction

7 0
3 years ago
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