A horse pulls a wagon forward. What is the equal and opposite force for the force of the horse pushing down on the ground as des
2 answers:
Answer:
The equal and opposite force is equal to the sum of any frictional force to the product of the mass of the wagon and the acceleration of the wagon
Explanation:
Newton's third law states that for every action, or force, there is an equal and opposite reaction
The equal and opposite force = The mass of the Wagon, m × The acceleration of the wagon, a + Any frictional force present,
Whereby the force with which the horse pulls the wagon = F, mathematically, we have;
The equal and opposite force = -F = m × a + .
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3s
Explanation:
Given parameters:
Mass of car = 1000kg
Force applied = 8000N
speed = 24m/s
Unknown:
time taken for the car to stop = ?
Solution:
According to newton's second law of motion; "the force on a body is the product of its mass and acceleration".
Force = mass x acceleration
let us find the acceleration of the car;
a = =
= 8m/s²
since the car is accelerating at a rate of 8m/s², when the brakes are applied, it will start decelerating at the constant rate, - 8m/s²
Applying the appropriate equation of motion;
V = U + at
V is the final velocity
U is the initial velocity
a is the acceleration
t is the time taken
final velocity = 0
0 = U + at
-U = at
-24 = -8t
t = 3s
learn more:
Newton's laws brainly.com/question/11411375
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