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2 years ago

1. What is the surface area of the cube

Mathematics

2 answers:

Marrrta [24]2 years ago

5 0

Answer:

96 in. squared

Step-by-step explanation:

JulsSmile [24]2 years ago

4 0

Answer:

80 in

Step-by-step explanation:

You might be interested in

F(x) = 3x + x3

____ [38]

Answer:

Please check the explanation.

Step-by-step explanation:

Given

f(x) = 3x + x³

Taking differentiate

$\frac{d}{dx}\left(3x+x^3\right)$

$\mathrm{Apply\:the\:Sum/Difference\:Rule}:\quad \left(f\pm g\right)'=f\:'\pm g'$

$=\frac{d}{dx}\left(3x\right)+\frac{d}{dx}\left(x^3\right)$

solving

$\frac{d}{dx}\left(3x\right)$

$\mathrm{Take\:the\:constant\:out}:\quad \left(a\cdot f\right)'=a\cdot f\:'$

$=3\frac{d}{dx}\left(x\right)$

$\mathrm{Apply\:the\:common\:derivative}:\quad \frac{d}{dx}\left(x\right)=1$

$=3\cdot \:1$

$=3$

now solving

$\frac{d}{dx}\left(x^3\right)$

$\mathrm{Apply\:the\:Power\:Rule}:\quad \frac{d}{dx}\left(x^a\right)=a\cdot x^{a-1}$

$=3x^{3-1}$

$=3x^2$

Thus, the expression becomes

$\frac{d}{dx}\left(3x+x^3\right)=\frac{d}{dx}\left(3x\right)+\frac{d}{dx}\left(x^3\right)$

$=3+3x^2$

Thus,

f'(x) = 3 + 3x²

Given that f'(x) = 15

substituting the value f'(x) = 15 in f'(x) = 3 + 3x²

f'(x) = 3 + 3x²

15 = 3 + 3x²

switch sides

3 + 3x² = 15

3x² = 15-3

3x² = 12

Divide both sides by 3

x² = 4

$\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}$

$x=\sqrt{4},\:x=-\sqrt{4}$

$x=2,\:x=-2$

Thus, the value of x will be:

$x=2,\:x=-2$

5 0

2 years ago

What is f(-4) if f(x)=|7x-3|

MrRissso [65]

Substitute the given into the function

f(-4) = |7(-4) - 3|
now solve
f(-4) = |-28 - 3|
f(-4) = | -31|
the absolute value of |-31| is 31
so,
f(-4) = 31

Hope this helps :)

8 0

2 years ago

Read 2 more answers

The partial pressure of carbon dioxide in a mixture is 0.31 atm.

juin [17]

Answer:

$P_{Co2}= X_{Co2} P_{tot}$

Where $P_{tot}$ represent the total pressure and $X_{Co2}$ the fraction of carbon dioxide is 0.46 and we can find the total pressure with this formula:

$P_{tot}= \frac{P_{Co2}}{X_{Co2}}$

And replacing we got:

$P_{tot}= \frac{0.31 atm}{0.46}= 0.674 atm$

Step-by-step explanation:

For this case the partial presure of carbon dioxide is given by:

$P_{Co2}= X_{Co2} P_{tot}$

Where $P_{tot}$ represent the total pressure and $x_{Co2}$ the fraction of carbon dioxide is 0.46 and we can find the total pressure with this formula: