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trapecia [35]
3 years ago
8

How many meters is 7.3 kilometers? 1km=1000m

Mathematics
2 answers:
serg [7]3 years ago
8 0

Answer:

7,300 meters

Step-by-step explanation:

7.3×1000 = 7300

jarptica [38.1K]3 years ago
3 0
It is 7300 bc 7.3x1000=7300
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In 2010, the world's largest pumpkin weighed 1,810 kilograms. An average-sized pumpkin weighs 5,000 grams.
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Select all the correct answers. If the measure of angle 0 is 5(pi)/4, which statements are true?
elixir [45]

Finding the equivalent angle of \theta, the correct statements are given as follows:

  • The Measure of the reference angle is 45.
  • \cos{\theta} = \frac{\sqrt{2}{2}}.
  • \tan{\theta} = 1
  • \sin{\theta} = \frac{\sqrt{2}{2}}.

<h3>What are equivalent angles?</h3>

Each angle on the second, third and fourth quadrants will have an equivalent on the first quadrant.

In this problem, the given angle is as follows:

\theta = \frac{5\pi}{4}

It is on the third quadrant, as it is between pi and 1.5 pi, hence the equivalent on the first quadrant, also known as the reference angle, is given by:

\frac{5\pi}{4} - \pi = \frac{5\pi}{4} - \frac{4\pi}{4} = \frac{\pi}{4}

The angle of 45º has equal sine and cosine, and tangent of 1, hence the correct statements are:

  • The Measure of the reference angle is 45.
  • \cos{\theta} = \frac{\sqrt{2}{2}}.
  • \tan{\theta} = 1
  • \sin{\theta} = \frac{\sqrt{2}{2}}.

More can be learned about equivalent angles at brainly.com/question/24787111

#SPJ1

8 0
1 year ago
two mountain bikers leave from the same parking lot and head in opposite directions on two different trails. the first rider goe
sveta [45]

Applying the required <em>rule </em>or <em>theorem</em>, it can be concluded that the second biker is <u>farther</u> from the <em>parking lot</em>. The distance of the bikers to the <em>parking lot</em> are:

i. First biker = 17.0 km

ii. Second biker = 20.22 km

The <u>path</u> of travel of both bikers would form a triangle. Applying the <u>Pythagoras</u> theorem to the path of the <em>first</em> biker would give his <u>distance</u> from the starting point. While applying the <u>cosine</u> rule to the path of <em>second</em> rider would gives his <u>distance</u> to the starting point.

Thus,

a. <u>To determine the distance of the first biker from the parking lot.</u>

Let the required <em>distance </em>be represented by x. Applying the Pythagoras theorem, we have:

hyp^{2} = adj 1^{2} + adj 2^{2}

x^{2} = 8^{2} + 15^{2}

   = 64 + 225

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x = \sqrt{289}

  = 17

x = 17 km

Thus, the <u>first</u> biker is 17.0 km from the <em>starting</em> point.

b. <u>To determine the distance of the second biker from the parking lot.</u>

Let the required <em>distance</em> be represented by x. So that applying the cosine rule, we have:

c^{2} = a^{2} + b^{2} - 2ab Cos θ

x^{2} = 8^{2} + 15^{2} - 2(15*8) Cos (180 - 20)

    = 64 + 225 - 240 Cos 160

    = 289 - 240 * -0.5

x^{2} = 289 + 120

   = 409

x = \sqrt{409}

 = 20.2237

x = 20.22 km

Thus, the <u>second</u> biker is 20.22 km from the <em>starting</em> point.

Therefore, the second biker is <u>farther</u> from the <em>parking lot</em>.

A sketch of the path of travel for the two bikers is attached for more clarifications.

Visit: brainly.com/question/22699651

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