Answer:
After 6sec 5 atoms will be left.
Explanation:
Given data:
Total atoms of Highlinium = 40
Half life = 2 sec
Atoms left after 6sec = ?
Solution:
First of all we will calculate the number of half lives passes during 6sec.
Number of half lives = Time elapsed/ half life
Number of half lives = 6 sec / 2sec
Number of half lives = 3
Now we will calculate the number of atoms left
At time zero = 40 atoms
At 1st half life = 40 atoms/2 = 20 atoms
At 2nd half life = 20 atoms/2 = 10 atoms
At 3rd half life = 10 atoms / 2 = 5 atoms
Thus, after 6sec 5 atoms will be left.
The amount of energy in kilocalories released from 49 g of glucose given the data is -4.4 Kcal
How to determine the mole of glucose
Mass of glucose = 49 g
Molar mass of glucose = 180.2 g/mol
Mole of glucose = ?
Mole = mass / molar mass
Mole of glucose = 49 / 180.2
Mole of glucose = 0.272 mole
How to determine the energy released
C₆H₁₂O₆ →2C₂H₆O + 2CO₂ ΔH = -16 kcal/mol
From the balanced equation above,
1 mole of glucose released -16 kcal of energy
Therefore,
0.272 mole of glucose will release = 0.272 × -16 = -4.4 Kcal
Thus, -4.4 Kcal were released from the reaction
Learn more about stoichiometry:
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<span>Major factor which is not a part of the chemical structure that promotes the formation of solutions is the inter molecular forces between them. Also the entropy that is created in the dissolving solvent also considerably effects the solution formation</span>
Answer: Option A) dissolving sugar in water
Explanation:
Sugar belongs to the class of food nutrients called carbohydrates, and it contains high energy bonds in its atoms that reacts with water thereby spontaneously releasing energy (in form of heat) to the surroundings.
Unlike others, energy is released when sugar is dissolved in water, thus the reaction is an example of exothermic reaction.
