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Anvisha [2.4K]
3 years ago
10

Help please it’s confusing to me

Chemistry
1 answer:
Colt1911 [192]3 years ago
6 0

Answer:

B, H, E, G, C, D, A, F

Explanation:

The ones closest to the bottom are the oldest

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stellarik [79]

Answer:

Am

Explanation:

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3 years ago
An empty beaker is weighed and found to weigh 23.1 g. Some potassium chloride is then added to the beaker and weighed again. The
GuDViN [60]

Answer:Mass of Potassium chloride =1.762g

Explanation:

Mass of empty beaker = 23.100 g

Mass of beaker with Potassium chloride = 24.862g

Mass of Potassium chloride = Final weight - initial weight = Mass of beaker with Potassium chloride  - Mass of empty beaker = 24.862-23.100 = 1.762g

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3 years ago
A molecule with 14 total electrons and 12 total protons
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Answer:

Explanation:

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5 0
3 years ago
How are properties useful in classifying materials
lukranit [14]
S. Properties can be anything from composition to color to ductility. Without knowing an object's properties, it is impossible to characterize it. For example, looking at some common properties of metals helps to differentiate them from non-metals or metalloids.
5 0
4 years ago
Read 2 more answers
A sample of krypton has a volume of 6.00 L, and the pressure is 0.960 atm. If the final temperature is 55.0°C, the final volume
MissTica

193.38 K was the initial temperature of the krypton.

Explanation:

Data given:

Initial volume of the krypton gas = 6 litres

initial pressure of the krypton gas = 0.960 atm

initial temperature of the krypton gas = ?

final volume of the krypton gas  = 7.70 litres

final pressure of the Krypton gas  = 1.25 atm

final temperature of the krypton gas = 55 degrees or 273.25+55 = 323.15 K

Applying the  Combined Gas Laws:

\frac{P1V1}{T1} = \frac{P2V2}{T2}

Rearranging the equation:

T1  = \frac{P1V1T2}{P2V2}

Putting the value in the equation:

T1 = \frac{0.960 X 6 X 323.15}{1.25 X 7.70}

T1 = 193.38 K

Initial temperature of the krypton gas is 193.78 K

5 0
4 years ago
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