Answer:
28.6 kg
Explanation:
The final weight can be calculated from the mixing data and formulae which is given as follows:
cement content =
Computing the parameters and checking the tables gives 28.6 kg.
Answer:
Pressure = 610.125 kPa
Explanation:
Given:
Mass of the air, m = 0.3 kg
Volume of the cylinder, V = 42.9 litres = 42.9 × 10⁻³ m³
R value for the air = 287 J/kg/K
Temperature, T = 31.0° C = 304 K
Now,
we know the ideal gas equation is given as :
PV=mRT
where,
P is the pressure
on substituting the values, in the above formula
we get
P × 42.9 × 10⁻³ = 0.3 × 287 × 304
or
P = 610125.87 Pa
or
P = 610.125 kPa
Answer:
I think it is 10 percent because
Answer:
0.577
Explanation:
Answer:
Explanation:
Parameters given:
Angle = 30°
Mass of block = 5kg
Velocity = 6 m/s
Time = 4s
Frictional force is given in terms of Normal force as:
F = uN
Where u = coefficient of frictional force
N = normal force
Frictional force is given as:
F = mgsinθ
Normal force is given as:
N = mgcosθ
Coefficient of friction is therefore given as:
mgsinθ = u * mgcosθ
=> u = sinθ / cosθ
u = tanθ
u = tan(30°)
u = 0.577
Answer:
C. 14.55
Explanation:
12 x 10 = 120
120 divded by 10 is 12
so now we do the left side
7 x 3 = 21 divded by 10 is 2
so now we have 14
and the remaning area is 0.55
so 14.55