Two satellites A and B are orbiting the earth around the equator, E, at different altitudes on a circular path of 2400km and 300
1 answer:
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Explanation:
(a)
Here, distance between hosts A and B is m meters and, propagation speed along the link is s meter/sec
Hence, propagation delay,
(b)
Here, size of the packet is L bits
And the transmission rate of the link is R bps
Hence, the transmission time of the packet,
(c)
As we know, end-to-end delay or total no delay,
(d)
The expression, time means the\at time since transmission started is equal to transmission delay.
As we know, transmission delay is the time taken by host to push out the packet.
Hence, at the last bit of the packet has been pushed out or transmitted.
(e)
If
Then, at the bit has been transmitted from host A, but to condition (1), the first bit has not reached B.
(f)
If
Then, at , the first bit has reached destination on B
Here,
It's given that
Hence,