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Mice21 [21]
2 years ago
8

Two satellites A and B are orbiting the earth around the equator, E, at different altitudes on a circular path of 2400km and 300

0km from the surface of the earth. The radius of the earth at the equator is its equatorial radius which is 6378km, mass of the earth is 5.98*10^24kg, g=9.81m/s^2, G=m^2/kg^2. If the satellites are of the same mass, 100kg, determine the:
a) Force required to keep each satellite in orbit.
b) Speed of the satellite and which is at a higher speed around the earth.
c) The period and the angular frequency of the satellites around the earth.
d) Force of attraction between the earth and each satellite, fA and fB.
Engineering
1 answer:
White raven [17]2 years ago
7 0
Fhdjdi where jdwygd dhskeuff jdhehdu heir bdjdkdj
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Air modeled as an ideal gas enters a well-insulated diffuser operating at steady state at 270 K with a velocity of 180 m/s and e
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Answer:

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Explanation:

given data

temperature T1 = 270 K

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solution

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so we write here energy balance equation that is

0 = m (h1-h2) + m ×  (\frac{v1^2}{2}-\frac{v2^2}{2})   .....................1

so it will be

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270.11 + \frac{180^2\times \frac{1}{1000}}{2} = h2 + \frac{48.4^2\times \frac{1}{1000}}{2}  

solve it we get

h2 = 285.14 kJ/kg

so by the ideal gas table we get

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