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DaniilM [7]
2 years ago
5

An earth fill, when compacted will occupy a net volume of 187,000 cy. The borrow material that will be used to construct this fi

ll is a stiff clay. In this “bank” condition, the borrow material has a wet unit weight of 129 lb per cubic foot (cf), a water content (w %) of 16.5%, and an in-place void ratio (e) of 0.620. The fill will be constructed in layers of 6 inch depth, loose measure, and compacted to a dry unit weight (Yd ) of 114 lb per cf at a moisture content of 18.3%...
Engineering
1 answer:
salantis [7]2 years ago
5 0

The <em>required</em> volume of borrow pit excavation was gotten as;

<em><u>V_net,borr ≈ 192,054 cy</u></em>

The missing part of the question is;

Compute the required volume of borrow pit excavation.

  • We are given;

Net volume of earth fill; V_net,fill = 187,000 cy

<em>Wet unit weight</em> of borrow material; γ_wet = 129 lb/ft³

Water content; m = 16.5% = 0.165

<em>Dry unit weight</em> of fill yard; γ_d,fill = 114 lb/cf

  • Now, to get the dry unit weight of the borrowed material, we will use the formula;

γ_d = γ_wet/(1 + m)

Plugging in the relevant values, we have;

γ_d,borr = 129/(1 + 0.65)

γ_d,borr = 111 lb/cf

     Since the net volume is in cy units, then let us convert the dry volumes to lb/cy.

Thus, from conversion tables, we have;

γ_d,fill = 114 lb/cf × 27 cf/cy

γ_d,fill = 3078 lb/cy

Similarly;

γ_d,borr = 111 lb/cf × 27 cf/cy

γ_d,borr = 2997 lb/cy

Thus, to find the volume of the borrow pit excavation, we will use the formula;

V_net,fill × γ_d,fill = V_net,borr × γ_d,borr

Plugging in the relevant values gives us;

187,000cy × 3078 lb/cy = V_net,borr × 2997 lb/cy

Thus;

V_net,borr = (187000 × 3078)/2997

<em>V_net,borr ≈ 192,054 cy</em>

Read more at; brainly.com/question/15090365

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Answer:

1) the volume of solid (Vs) is 4733.33 ft³

2) the total cost to pay Pit A is $58220

3) the total cost to pay to Pit B is $53344.67

4) the total cost to pay to Pit C is $34269.32

5) the total cost to pay to Pit D is $49132.02

Explanation:  

given the data in the question;

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1) Calculate the volume of solid (Vs)

Vs = V / ( 1 + e )

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Vs = 7100 / ( 1 + 0.5 )

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Vpitb / Vcomp = ( 1 + e_{PHB}) / ( 1 + e_{comp )

we substitute

VpitB / 7100 = ( 1 + 0.61) / ( 1 + 0.5)

VpitB / 7100 = 1.0733333

VpitB = 1.0733333 × 7100

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Total cost = volume × unit cost = 7620.666 × 7 = $53344.67

Therefore, the total cost to pay to Pit B is $53344.67

4) Calculate the total cost to pay to Pit C = Borrow Pit D: void ratio = 0.73 and the unit cost = $6 /ft3

VpitC / Vcomp = ( 1 + e_{PHC}) / ( 1 + e_{comp )

we substitute

VpitC / 7100 = ( 1 + 0.81) / ( 1 + 0.5)

VpitC / 7100 = 1.2066666

VpitC = 1.2066666× 7100

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we substitute

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VpitD / 7100 = 1.1533333

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Therefore, the total cost to pay to Pit D is $49132.02

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