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3 years ago

8

The dog grooming service in Pet Smart charges according to the dog’s weight. For dogs weighing 15 pounds or less, the grooming f

ee is $35.00. For dogs weighing more than 15 pounds and up to 40 pounds, the fee is $40.00. And for dogs weighing over 40 pounds, the fee is $40.00, plus $0.25 for each additional pound over 40. What is the absolute value of the difference in grooming service fee for a 65 pound dog and a 32 pound dog?

1

1 answer:

Elanso [62]3 years ago

6 0

The total amount of money to groom the 65 pound dog is $46.25, the price for grooming the $32 pound dog is $40, $46.25-$40=$6.25

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Solve for x ???????????

Aleks04 [339]

Do you recognize that the hypotenuse here has the length 22 and that the opposite side is the unknown (x)? The angle is 21 degrees.

This is a perfect application of the tangent function:

tan 21 deg = opp / adj = opp / 22 = x / 22

tan 21 deg = 0.384 so x would be 22 tan 21 deg, or
x = 22*(0.384)
= 8.45 (answer)

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3 years ago

Describe the steps to dividing imaginary numbers and complex numbers with two terms in the denominator?

zlopas [31]

Answer:

Let be a rational complex number of the form $z = \frac{a + i\,b}{c + i\,d}$ , we proceed to show the procedure of resolution by algebraic means:

1) $\frac{a + i\,b}{c + i\,d}$ Given.

2) $\frac{a + i\,b}{c + i\,d} \cdot 1$ Modulative property.

3) $\left(\frac{a+i\,b}{c + i\,d} \right)\cdot \left(\frac{c-i\,d}{c-i\,d} \right)$ Existence of additive inverse/Definition of division.

4) $\frac{(a+i\,b)\cdot (c - i\,d)}{(c+i\,d)\cdot (c - i\,d)}$ $\frac{x}{y}\cdot \frac{w}{z} = \frac{x\cdot w}{y\cdot z}$

5) $\frac{a\cdot (c-i\,d) + (i\,b)\cdot (c-i\,d)}{c\cdot (c-i\,d)+(i\,d)\cdot (c-i\,d)}$ Distributive and commutative properties.

6) $\frac{a\cdot c + a\cdot (-i\,d) + (i\,b)\cdot c +(i\,b) \cdot (-i\,d)}{c^{2}-c\cdot (i\,d)+(i\,d)\cdot c+(i\,d)\cdot (-i\,d)}$ Distributive property.

7) $\frac{a\cdot c +i\,(-a\cdot d) + i\,(b\cdot c) +(-i^{2})\cdot (b\cdot d)}{c^{2}+i\,(c\cdot d)+[-i\,(c\cdot d)] +(-i^{2})\cdot d^{2}}$ Definition of power/Associative and commutative properties/ $x\cdot (-y) = -x\cdot y$ /Definition of subtraction.

8) $\frac{(a\cdot c + b\cdot d) +i\cdot (b\cdot c -a\cdot d)}{c^{2}+d^{2}}$ Definition of imaginary number/ $x\cdot (-y) = -x\cdot y$ /Definition of subtraction/Distributive, commutative, modulative and associative properties/Existence of additive inverse/Result.

Step-by-step explanation:

Let be a rational complex number of the form $z = \frac{a + i\,b}{c + i\,d}$ , we proceed to show the procedure of resolution by algebraic means:

1) $\frac{a + i\,b}{c + i\,d}$ Given.

2) $\frac{a + i\,b}{c + i\,d} \cdot 1$ Modulative property.

3) $\left(\frac{a+i\,b}{c + i\,d} \right)\cdot \left(\frac{c-i\,d}{c-i\,d} \right)$ Existence of additive inverse/Definition of division.

4) $\frac{(a+i\,b)\cdot (c - i\,d)}{(c+i\,d)\cdot (c - i\,d)}$ $\frac{x}{y}\cdot \frac{w}{z} = \frac{x\cdot w}{y\cdot z}$

5) $\frac{a\cdot (c-i\,d) + (i\,b)\cdot (c-i\,d)}{c\cdot (c-i\,d)+(i\,d)\cdot (c-i\,d)}$ Distributive and commutative properties.

6) $\frac{a\cdot c + a\cdot (-i\,d) + (i\,b)\cdot c +(i\,b) \cdot (-i\,d)}{c^{2}-c\cdot (i\,d)+(i\,d)\cdot c+(i\,d)\cdot (-i\,d)}$ Distributive property.

7) $\frac{a\cdot c +i\,(-a\cdot d) + i\,(b\cdot c) +(-i^{2})\cdot (b\cdot d)}{c^{2}+i\,(c\cdot d)+[-i\,(c\cdot d)] +(-i^{2})\cdot d^{2}}$ Definition of power/Associative and commutative properties/ $x\cdot (-y) = -x\cdot y$ /Definition of subtraction.

8) $\frac{(a\cdot c + b\cdot d) +i\cdot (b\cdot c -a\cdot d)}{c^{2}+d^{2}}$ Definition of imaginary number/ $x\cdot (-y) = -x\cdot y$ /Definition of subtraction/Distributive, commutative, modulative and associative properties/Existence of additive inverse/Result.

3 0

2 years ago

Time spent using e-mail per session is normally distributed, with mu equals 11 minutes and sigma equals 3 minutes. Assume that

liq [111]

Answer:

a) 0.259

b) 0.297

c) 0.497

Step-by-step explanation:

To solve this problem, it is important to know the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$

In this problem, we have that:

$\mu = 11, \sigma = 3$

a. If you select a random sample of 25 sessions, what is the probability that the sample mean is between 10.8 and 11.2 minutes?

Here we have that $n = 25, s = \frac{3}{\sqrt{25}} = 0.6$

This probability is the pvalue of Z when X = 11.2 subtracted by the pvalue of Z when X = 10.8.

X = 11.2

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{11.2 - 11}{0.6}$

$Z = 0.33$

$Z = 0.33$ has a pvalue of 0.6293.

X = 10.8

$Z = \frac{X - \mu}{s}$

$Z = \frac{10.8 - 11}{0.6}$

$Z = -0.33$

$Z = -0.33$ has a pvalue of 0.3707.

0.6293 - 0.3707 = 0.2586

0.259 probability, rounded to three decimal places.

b. If you select a random sample of 25 sessions, what is the probability that the sample mean is between 10.5 and 11 minutes?

Subtraction of the pvalue of Z when X = 11 subtracted by the pvalue of Z when X = 10.5. So

X = 11

$Z = \frac{X - \mu}{s}$

$Z = \frac{11 - 11}{0.6}$

$Z = 0$

$Z = 0$ has a pvalue of 0.5.

X = 10.5

$Z = \frac{X - \mu}{s}$

$Z = \frac{10.5 - 11}{0.6}$

$Z = -0.83$

$Z = -0.83$ has a pvalue of 0.2033.

0.5 - 0.2033 = 0.2967

0.297, rounded to three decimal places.

c. If you select a random sample of 100 sessions, what is the probability that the sample mean is between 10.8 and 11.2 minutes?

Here we have that $n = 100, s = \frac{3}{\sqrt{100}} = 0.3$

This probability is the pvalue of Z when X = 11.2 subtracted by the pvalue of Z when X = 10.8.

X = 11.2

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{11.2 - 11}{0.3}$

$Z = 0.67$

$Z = 0.67$ has a pvalue of 0.7486.

X = 10.8

$Z = \frac{X - \mu}{s}$

$Z = \frac{10.8 - 11}{0.3}$

$Z = -0.67$

$Z = -0.67$ has a pvalue of 0.2514.

0.7486 - 0.2514 = 0.4972

0.497, rounded to three decimal places.

5 0

3 years ago

Question 4 of 10 A construction worker needs to put a rectangular window in the side of a building. He knows from measuring that

vagabundo [1.1K]

Answer:

❝ D. 13 feet ❞

Step-by-step explanation:

Here,

Window is in the rectangular shape.
Measure of its one diagonal is 13 feet.

According to the properties of rectangle,

→ Diagonals of a rectangle are equal.

So, here the length of other diagonal will be 13 feet too.

7 0

3 years ago

Help ASAP please ..<br> Explain answer ..

Luba_88 [7]

Answer:

C

Step-by-step explanation:

Becuase it is the number of caleders purchesed times how many calenders

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3 years ago

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