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ExtremeBDS [4]
2 years ago
14

Members of a school sports team are raising money by selling custom water bottles at school activities. They plan to sell each b

ottle for $13. Each bottle costs them $6. They spend $40 for advertising. Use n to represent the number of bottles they sell. Multiply this by the money they make for each bottle, then subtract the advertising cost. Which expression represents the money that the group raises? O A. 40 - (13 - 6)n O B. (13 - 6) n - 40 O C. 13n - 6 - 40 D. 13-on-40​
Mathematics
1 answer:
andre [41]2 years ago
5 0

Answer:

B. (13 - 6)n - 40

Step-by-step explanation:

If each bottle costs them $6 and they are selling each one for $13, the amount of money they make for each bottle can be represented by (13 - 6)n

This is because this finds the profit per bottle, then multiplies it by n, which is the number of bottles they sell.

Then, since they spent $40 on advertising, subtract 40 from this.

The expression will be (13 - 6)n - 40.

The correct answer is B. (13 - 6)n - 40

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V125BC [204]
Answer: 7 π r² + π r³

Explanation:

1) The general formula for the volumen, V, of a cylinder with radius r and height h is:

V = π r² h

2) Now you have the condition that the height is 7 inches greater than the radius, that is:

h = 7 + r

3) Replace h with its expression

V = π r² (7 + r)

4) Expand the product (use distributive property):

V = π (7r²) + π r³ = 7 π r² + π r³

Answer: 7 π r² + π r³

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3 years ago
Find the value of Q. No links plz.
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Answer:

(rounded)17.2=Q

Step-by-step explanation:

Q= 13/cos41

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Q1 a) Kamahi invests some money which earns compound interest every year. His investment
gulaghasi [49]

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Step-by-step explanation:

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2 years ago
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15600=x (x+1)(x+2) What is x?
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3 years ago
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Simplify the complex fraction.
lilavasa [31]

Given:

$\frac{\left(\frac{(4 r)^{3}}{15 t^{4}}\right)}{\left(\frac{16 r}{(3 t)^{2}}\right)}

To find:

The simplified fraction.

Solution:

Step 1: Simplify the numerator

$\frac{(4 r)^{3}}{15 t^{4}}=\frac{4^3 r^{3}}{15 t^{4}}=\frac{64 r^{3}}{15 t^{4}}

Step 2: Simplify the denominator

$\frac{16 r}{(3 t)^{2}}=\frac{16 r}{3^2 t^{2}}= \frac{16 r}{9 t^{2}}

Step 3: Using step 1 and step 2

$\frac{\left(\frac{(4 r)^{3}}{15 t^{4}}\right)}{\left(\frac{16 r}{(3 t)^{2}}\right)}=\frac{\left(\frac{64 r^{3}}{15 t^{4}}\right)}{\left(\frac{16 r}{9 t^{2}} \right)}

Step 4: Using fraction rule:

$\frac{\frac{a}{b}}{\frac{c}{d}}=\frac{a \cdot d}{b \cdot c}

$\frac{\left(\frac{64 r^{3}}{15 t^{4}}\right)}{\left(\frac{16 r}{9 t^{2}}\right)}=\frac{64r^3 \cdot 9t^2}{16 r \cdot 15 t^4}

Cancel the common factor r and t², we get

           $=\frac{64 r^{2} \cdot 9 }{16  \cdot 15 t^2 }

Cancel the common factors 16 and 3 on both numerator and denominator.

           $=\frac{4 r^{2} \cdot 3 }{  5 t^2 }

           $=\frac{12 r^{2}  }{  5 t^2 }

$\frac{\left(\frac{(4 r)^{3}}{15 t^{4}}\right)}{\left(\frac{16 r}{(3 t)^{2}}\right)}=\frac{12 r^{2}  }{  5 t^2 }

The simplified fraction is \frac{12 r^{2}  }{  5 t^2 }.

5 0
3 years ago
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